6.4.10 CYU

6.4.10 CYU

Assessment

Flashcard

Mathematics

6th Grade

Hard

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15 questions

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1.

FLASHCARD QUESTION

Front

What is the volume of a cube with edge length 4 inches?

Back

The volume of a cube is calculated using the formula V = side^3. For a cube with edge length 4 inches, V = 4^3 = 64 cubic inches.

2.

FLASHCARD QUESTION

Front

How many little cubes with edge length \( \frac{1}{2} \) inch fit into a larger cube with edge length 4 inches?

Back

To find the number of little cubes, calculate the volume of the larger cube (4^3 = 64 cubic inches) and the volume of one little cube (\( \left(\frac{1}{2}\right)^3 = \frac{1}{8} \) cubic inches). Then, divide the volume of the larger cube by the volume of one little cube: \( 64 \div \frac{1}{8} = 64 \times 8 = 512 \).

3.

FLASHCARD QUESTION

Front

What expression can be used to find how many cubes with edge length of \( \frac{1}{3} \) unit fit in a prism that is 5 units by 5 units by 8 units?

Back

The expression is \( (5 \cdot 3) \cdot (5 \cdot 3) \cdot (8 \cdot 3) \). This calculates the number of cubes along each dimension.

4.

FLASHCARD QUESTION

Front

What is \( \frac{5}{6} \div \frac{1}{2} \)?

Back

To divide fractions, multiply by the reciprocal: \( \frac{5}{6} \times \frac{2}{1} = \frac{10}{6} = 1\frac{2}{3} \).

5.

FLASHCARD QUESTION

Front

What is \( \frac{8}{9} \div \frac{2}{3} \)?

Back

To divide fractions, multiply by the reciprocal: \( \frac{8}{9} \times \frac{3}{2} = \frac{24}{18} = 1\frac{1}{3} \).

6.

FLASHCARD QUESTION

Front

What is \( \frac{7}{8} \div \frac{1}{4} \)?

Back

To divide fractions, multiply by the reciprocal: \( \frac{7}{8} \times \frac{4}{1} = \frac{28}{8} = 3\frac{1}{2} \).

7.

FLASHCARD QUESTION

Front

Define volume in the context of geometry.

Back

Volume is the amount of space occupied by a three-dimensional object, measured in cubic units.

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