Distance Formula

Distance Formula

Assessment

Flashcard

Mathematics

9th - 11th Grade

Hard

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14 questions

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1.

FLASHCARD QUESTION

Front

What is the Distance Formula?

Back

The Distance Formula is used to determine the distance between two points in a coordinate plane. It is given by the formula: d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}.

2.

FLASHCARD QUESTION

Front

How do you find the distance between the points (3, 24) and (7, 56)?

Back

Using the Distance Formula: d = \sqrt{(7 - 3)^2 + (56 - 24)^2} = \sqrt{4^2 + 32^2} = \sqrt{16 + 1024} = \sqrt{1040} \approx 32.2.

3.

FLASHCARD QUESTION

Front

What is the distance between the points (2, 0) and (-2, 4)?

Back

Using the Distance Formula: d = \sqrt{(-2 - 2)^2 + (4 - 0)^2} = \sqrt{(-4)^2 + 4^2} = \sqrt{16 + 16} = \sqrt{32} \approx 5.7.

4.

FLASHCARD QUESTION

Front

Calculate the distance between the points (0, 0) and (3, 4).

Back

Using the Distance Formula: d = \sqrt{(3 - 0)^2 + (4 - 0)^2} = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5.

5.

FLASHCARD QUESTION

Front

What is the distance between the points (1, 2) and (4, 6)?

Back

Using the Distance Formula: d = \sqrt{(4 - 1)^2 + (6 - 2)^2} = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5.

6.

FLASHCARD QUESTION

Front

Find the distance between the points (-1, -1) and (2, 3).

Back

Using the Distance Formula: d = \sqrt{(2 - (-1))^2 + (3 - (-1))^2} = \sqrt{(3)^2 + (4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5.

7.

FLASHCARD QUESTION

Front

What is the distance between the points (5, 5) and (5, 10)?

Back

Using the Distance Formula: d = \sqrt{(5 - 5)^2 + (10 - 5)^2} = \sqrt{0 + 25} = \sqrt{25} = 5.

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