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Mastering Rational Number Operations

Mastering Rational Number Operations

Assessment

Flashcard

•

Mathematics

•

8th Grade

•

Practice Problem

•

Hard

Created by

Wayground Content

FREE Resource

Student preview

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15 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What is a rational number?

Back

A rational number is any number that can be expressed as the quotient or fraction ab\frac{a}{b} , where aa is an integer and bb is a non-zero integer.

2.

FLASHCARD QUESTION

Front

How do you divide two rational numbers?

Back

To divide two rational numbers, multiply the first number by the reciprocal of the second number. For example, to divide 79\frac{7}{9} by 23\frac{2}{3} , calculate 79×32=7×39×2=2118=76\frac{7}{9} \times \frac{3}{2} = \frac{7 \times 3}{9 \times 2} = \frac{21}{18} = \frac{7}{6} .

3.

FLASHCARD QUESTION

Front

Convert the fraction 58\frac{5}{8} to a decimal.

Back

58=0.625\frac{5}{8} = 0.625 .

4.

FLASHCARD QUESTION

Front

What is the result of adding 34\frac{3}{4} and 23\frac{2}{3} ?

Back

To add 34\frac{3}{4} and 23\frac{2}{3} , find a common denominator (12): 34=912\frac{3}{4} = \frac{9}{12} and 23=812\frac{2}{3} = \frac{8}{12} . Thus, 912+812=1712\frac{9}{12} + \frac{8}{12} = \frac{17}{12} .

5.

FLASHCARD QUESTION

Front

How do you multiply two rational numbers?

Back

To multiply two rational numbers, multiply their numerators and denominators. For example, 25×34=2×35×4=620=310\frac{2}{5} \times \frac{3}{4} = \frac{2 \times 3}{5 \times 4} = \frac{6}{20} = \frac{3}{10} .

6.

FLASHCARD QUESTION

Front

What is the result of subtracting 56\frac{5}{6} from 78\frac{7}{8} ?

Back

To subtract 56\frac{5}{6} from 78\frac{7}{8} , find a common denominator (24): 78=2124\frac{7}{8} = \frac{21}{24} and 56=2024\frac{5}{6} = \frac{20}{24} . Thus, 2124−2024=124\frac{21}{24} - \frac{20}{24} = \frac{1}{24} .

7.

FLASHCARD QUESTION

Front

What is the reciprocal of a rational number?

Back

The reciprocal of a rational number ab\frac{a}{b} is ba\frac{b}{a} , provided that a≠0a \neq 0 .

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