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Implicit Differentiation

Implicit Differentiation

Assessment

Flashcard

•

Mathematics

•

12th Grade

•

Practice Problem

•

Hard

•
CCSS
8.F.B.4, HSF.IF.B.6

Standards-aligned

Created by

Wayground Content

FREE Resource

Student preview

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15 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What is Implicit Differentiation?

Back

Implicit differentiation is a technique used to differentiate equations where the dependent and independent variables are not separated. It allows us to find the derivative of y with respect to x when y is defined implicitly as a function of x.

2.

FLASHCARD QUESTION

Front

What is the derivative of a function?

Back

The derivative of a function at a point is the slope of the tangent line to the graph of the function at that point. It represents the rate of change of the function with respect to its variable.

3.

FLASHCARD QUESTION

Front

How do you apply implicit differentiation to the equation 3x2−6y3=133x^2 - 6y^3 = 13 ?

Back

Differentiate both sides with respect to x, treating y as a function of x. This gives 6x−18y2dydx=06x - 18y^2 \frac{dy}{dx} = 0 . Rearranging yields dydx=6x18y2=x3y2\frac{dy}{dx} = \frac{6x}{18y^2} = \frac{x}{3y^2} .

4.

FLASHCARD QUESTION

Front

What is the formula for the derivative of y with respect to x in implicit differentiation?

Back

The formula is dydx=−FxFy\frac{dy}{dx} = -\frac{F_x}{F_y} , where FxF_x is the partial derivative of the function with respect to x, and FyF_y is the partial derivative with respect to y.

5.

FLASHCARD QUESTION

Front

Differentiate the equation x3+y3=36x^3 + y^3 = 36 using implicit differentiation.

Back

Differentiating gives 3x2+3y2dydx=03x^2 + 3y^2 \frac{dy}{dx} = 0 . Solving for dydx\frac{dy}{dx} yields dydx=−x2y2\frac{dy}{dx} = -\frac{x^2}{y^2} .

6.

FLASHCARD QUESTION

Front

What is the derivative of 9y+x=4y9y + x = 4y ?

Back

Rearranging gives 9y−4y+x=09y - 4y + x = 0 . Differentiating gives 5dydx+1=05 \frac{dy}{dx} + 1 = 0 , leading to dydx=−15\frac{dy}{dx} = -\frac{1}{5} .

7.

FLASHCARD QUESTION

Front

How do you differentiate the equation −4x2+12x+6y2−10y=5-4x^2 + 12x + 6y^2 - 10y = 5 ?

Back

Differentiate both sides: −8x+12+12ydydx−10dydx=0-8x + 12 + 12y \frac{dy}{dx} - 10 \frac{dy}{dx} = 0 . Rearranging gives dydx=8x−1212y−10\frac{dy}{dx} = \frac{8x - 12}{12y - 10} .

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