Distance formulas

Distance formulas

Assessment

Flashcard

Mathematics

8th Grade

Practice Problem

Hard

CCSS
HSG.GPE.B.7, HSG.GPE.B.6, 8.G.B.8

Standards-aligned

Created by

Wayground Content

FREE Resource

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15 questions

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1.

FLASHCARD QUESTION

Front

What is the distance formula used to find the distance between two points (x1, y1) and (x2, y2)?

Back

Distance = √((x2 - x1)² + (y2 - y1)²)

Tags

CCSS.HSG.GPE.B.7

2.

FLASHCARD QUESTION

Front

What is the formula to find the midpoint between two points (x1, y1) and (x2, y2)?

Back

Midpoint = ((x1 + x2)/2, (y1 + y2)/2)

Tags

CCSS.HSG.GPE.B.6

3.

FLASHCARD QUESTION

Front

Calculate the distance between the points (2, 3) and (4, 7).

Back

Distance = √((4 - 2)² + (7 - 3)²) = √(4 + 16) = √20 = 4.47

Tags

CCSS.HSG.GPE.B.7

4.

FLASHCARD QUESTION

Front

Find the midpoint of the segment with endpoints (6, 8) and (2, 4).

Back

Midpoint = ((6 + 2)/2, (8 + 4)/2) = (4, 6)

Tags

CCSS.HSG.GPE.B.6

5.

FLASHCARD QUESTION

Front

What is the distance between the points (-1, -1) and (3, 3)?

Back

Distance = √((3 - (-1))² + (3 - (-1))²) = √(16 + 16) = √32 = 5.66

Tags

CCSS.HSG.GPE.B.7

6.

FLASHCARD QUESTION

Front

If a rectangular field has a width of 30 yards and a length of 40 yards, what is the distance across the field (diagonal)?

Back

Diagonal = √(30² + 40²) = √(900 + 1600) = √2500 = 50 yards

Tags

CCSS.8.G.B.8

7.

FLASHCARD QUESTION

Front

What is the distance between the points (0, 0) and (5, 12)?

Back

Distance = √((5 - 0)² + (12 - 0)²) = √(25 + 144) = √169 = 13

Tags

CCSS.HSG.GPE.B.7

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