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Distance between Two Points

Distance between Two Points

Assessment

Flashcard

•

Mathematics

•

8th Grade

•

Practice Problem

•

Hard

Created by

Wayground Content

FREE Resource

Student preview

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15 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What is the formula to calculate the distance between two points (x1, y1) and (x2, y2)?

Back

The distance formula is given by: d=(x2−x1)2+(y2−y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} .

2.

FLASHCARD QUESTION

Front

What is the distance between the points (3, 4) and (7, 1)?

Back

Using the distance formula: d=(7−3)2+(1−4)2=16+9=25=5d = \sqrt{(7 - 3)^2 + (1 - 4)^2} = \sqrt{16 + 9} = \sqrt{25} = 5 .

3.

FLASHCARD QUESTION

Front

Define 'hypotenuse' in the context of a right triangle.

Back

The hypotenuse is the longest side of a right triangle, opposite the right angle.

4.

FLASHCARD QUESTION

Front

What are the legs of a right triangle?

Back

The legs of a right triangle are the two sides that form the right angle.

5.

FLASHCARD QUESTION

Front

What is the Pythagorean theorem?

Back

The Pythagorean theorem states that in a right triangle, a2+b2=c2a^2 + b^2 = c^2 , where c is the length of the hypotenuse.

6.

FLASHCARD QUESTION

Front

If one leg of a right triangle is 6 units and the other leg is 8 units, what is the length of the hypotenuse?

Back

Using the Pythagorean theorem: c=62+82=36+64=100=10c = \sqrt{6^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10 .

7.

FLASHCARD QUESTION

Front

What is the distance between the points (1, 2) and (4, 6)?

Back

Using the distance formula: d=(4−1)2+(6−2)2=9+16=25=5d = \sqrt{(4 - 1)^2 + (6 - 2)^2} = \sqrt{9 + 16} = \sqrt{25} = 5 .

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