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Solving Quadratic Equations Using the Square Root Property

Solving Quadratic Equations Using the Square Root Property

Assessment

Flashcard

•

Mathematics

•

9th - 12th Grade

•

Practice Problem

•

Hard

Created by

Wayground Content

FREE Resource

Student preview

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15 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What is the square root property in solving quadratic equations?

Back

The square root property states that if x2=ax^2 = a , then x=±sqrt(a)x = ±\text{sqrt}(a) . This is used to find the solutions of quadratic equations.

2.

FLASHCARD QUESTION

Front

How do you isolate a squared term in an equation?

Back

To isolate a squared term, you can add or subtract other terms from both sides of the equation. For example, in (x−1)2=32(x-1)^2 = 32 , add 1 to both sides to isolate the squared term.

3.

FLASHCARD QUESTION

Front

What is the first step in solving (x−1)22=32\frac{(x-1)^2}{2} = 32 using the square root property?

Back

Multiply both sides by 2 to eliminate the fraction: (x−1)2=64(x-1)^2 = 64 .

4.

FLASHCARD QUESTION

Front

Solve x2=16x^2 = 16 using the square root property.

Back

x=±4x = ±4 .

5.

FLASHCARD QUESTION

Front

What does it mean if a quadratic equation has no real solutions?

Back

It means that the equation does not intersect the x-axis, and the solutions are complex or imaginary numbers.

6.

FLASHCARD QUESTION

Front

Solve −7x2+21=84-7x^2 + 21 = 84 for x.

Back

First, simplify to get −7x2=63-7x^2 = 63 , then x2=−9x^2 = -9 , which has no real solutions.

7.

FLASHCARD QUESTION

Front

What is the solution to (2x−1)2=49(2x - 1)^2 = 49 ?

Back

x=4x = 4 and x=−3x = -3 .

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