
Law of Sine and Law of Cosine
Flashcard
•
Mathematics
•
10th Grade
•
Hard
Wayground Content
FREE Resource
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14 questions
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1.
FLASHCARD QUESTION
Front
What is the Law of Sines?
Back
The Law of Sines states that in any triangle, the ratio of the length of a side to the sine of its opposite angle is constant. It can be expressed as: \( \frac{a}{\sin(A)} = \frac{b}{\sin(B)} = \frac{c}{\sin(C)} \)
2.
FLASHCARD QUESTION
Front
What is the Law of Cosines?
Back
The Law of Cosines relates the lengths of the sides of a triangle to the cosine of one of its angles. It is expressed as: \( c^2 = a^2 + b^2 - 2ab \cos(C) \)
3.
FLASHCARD QUESTION
Front
When do you use the Law of Sines?
Back
The Law of Sines is used when you have either two angles and one side (AAS or ASA) or two sides and a non-included angle (SSA) in a triangle.
4.
FLASHCARD QUESTION
Front
When do you use the Law of Cosines?
Back
The Law of Cosines is used when you have two sides and the included angle (SAS) or all three sides (SSS) of a triangle.
5.
FLASHCARD QUESTION
Front
Calculate the length of side c in a triangle with sides a = 5, b = 7, and angle C = 60°.
Back
Using the Law of Cosines: \( c^2 = 5^2 + 7^2 - 2 \cdot 5 \cdot 7 \cdot \cos(60°) \) \( c^2 = 25 + 49 - 35 = 39 \) \( c = \sqrt{39} \approx 6.24 \)
6.
FLASHCARD QUESTION
Front
Find the area of a triangle with sides a = 6 m, b = 8 m, and included angle C = 137°.
Back
Area = \( \frac{1}{2}ab \sin(C) = \frac{1}{2} \cdot 6 \cdot 8 \cdot \sin(137°) \approx 16.4 m² \)
7.
FLASHCARD QUESTION
Front
What is the formula for the area of a triangle using the Law of Sines?
Back
Area = \( \frac{1}{2}ab \sin(C) \), where a and b are the lengths of two sides and C is the included angle.
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