Law of Sine and Law of Cosine

Law of Sine and Law of Cosine

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Flashcard

Mathematics

10th Grade

Hard

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14 questions

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1.

FLASHCARD QUESTION

Front

What is the Law of Sines?

Back

The Law of Sines states that in any triangle, the ratio of the length of a side to the sine of its opposite angle is constant. It can be expressed as: \( \frac{a}{\sin(A)} = \frac{b}{\sin(B)} = \frac{c}{\sin(C)} \)

2.

FLASHCARD QUESTION

Front

What is the Law of Cosines?

Back

The Law of Cosines relates the lengths of the sides of a triangle to the cosine of one of its angles. It is expressed as: \( c^2 = a^2 + b^2 - 2ab \cos(C) \)

3.

FLASHCARD QUESTION

Front

When do you use the Law of Sines?

Back

The Law of Sines is used when you have either two angles and one side (AAS or ASA) or two sides and a non-included angle (SSA) in a triangle.

4.

FLASHCARD QUESTION

Front

When do you use the Law of Cosines?

Back

The Law of Cosines is used when you have two sides and the included angle (SAS) or all three sides (SSS) of a triangle.

5.

FLASHCARD QUESTION

Front

Calculate the length of side c in a triangle with sides a = 5, b = 7, and angle C = 60°.

Back

Using the Law of Cosines: \( c^2 = 5^2 + 7^2 - 2 \cdot 5 \cdot 7 \cdot \cos(60°) \) \( c^2 = 25 + 49 - 35 = 39 \) \( c = \sqrt{39} \approx 6.24 \)

6.

FLASHCARD QUESTION

Front

Find the area of a triangle with sides a = 6 m, b = 8 m, and included angle C = 137°.

Back

Area = \( \frac{1}{2}ab \sin(C) = \frac{1}{2} \cdot 6 \cdot 8 \cdot \sin(137°) \approx 16.4 m² \)

7.

FLASHCARD QUESTION

Front

What is the formula for the area of a triangle using the Law of Sines?

Back

Area = \( \frac{1}{2}ab \sin(C) \), where a and b are the lengths of two sides and C is the included angle.

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