Factoring and x-intercepts

Factoring and x-intercepts

SWBAT factor polynomials and find their x-intercepts.

Multiple Choice

Factor the following function

 $f\left(x\right)=x^2+8x+12$  

•  $f\left(x\right)=\left(x+1\right)\left(x+12\right)$  

•  $f\left(x\right)=\left(2x\right)\left(6x\right)$  

•  $f\left(x\right)=\left(x+4\right)\left(x+3\right)$  

•  $f\left(x\right)=\left(x+2\right)\left(x+6\right)$  

Multiple Choice

Factor the following function

 $f\left(x\right)=3x^2+10x+3$  

•  $f\left(x\right)=\left(x+9\right)\left(x+1\right)$  

•  $f\left(x\right)=\left(x+3\right)\left(3x+1\right)$  

•  $f\left(x\right)=\left(x+3\right)\left(x+1\right)$  

•  $f\left(x\right)=\left(3x+3\right)\left(x+1\right)$  

Multiple Choice

Factor

 $2x^3+2x^2-24x$  

•  $2x\left(x+12\right)\left(x-1\right)$  

•  $2x\left(x+4\right)\left(x-3\right)$  

•  $\left(x+8\right)\left(x-6\right)$  

•  $2\left(x-3\right)\left(x+4\right)$  

Multiple Choice

Factor

 $15x^3+20x^2+5x$  

•  $5x\left(3x+1\right)\left(x+1\right)$  

•  $\left(x+15\right)\left(x+5\right)$  

•  $5x\left(x+3\right)\left(x+1\right)$  

•  $5\left(x+1\right)\left(3x+1\right)$  

Multiple Choice

What is another name for the x-intercepts of a quadratic?

• y-intercept

• x-axis

• zeros

• they don't have another name

Fill in the Blanks

What are the zeroes to the following function. Answer using a complete sentence.

 $f\left(x\right)=\left(x+3\right)\left(x-11\right)$  

Multiple Choice

What are the x-intercepts to the following function

 $f\left(x\right)=3x\left(2x+1\right)\left(x-3\right)$  

•  $x=3,\ -1,\ 0$  

•  $x=-\frac{1}{2},\ 0,\ 3$  

•  $x=-\frac{1}{2},\ 3$  

•  $x=3,\ \frac{2}{3}$  

Fill in the Blanks

What are the x-intercepts to the function

 $h\left(x\right)=x\left(2x+1\right)\left(3x+7\right)$  

Multiple Choice

What are the x-intercepts to

 $f\left(x\right)=4x^3+12x^2+8x$  

• The x- intercepts to the function are $x=0,\ x=-1,\ x=-2$  

•  $x=-2,x=-1,\ x=0$  are the x-intercepts to the function.

Multiple Choice

Divide

 $\frac{\left(4x^2-24x+35\right)}{2x-5}$  

• 2x+12

• 2x-7

• 2x-12

• 2x+7