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3.1 Writing Quadratic Equations

3.1 Writing Quadratic Equations

Assessment

Presentation

Mathematics

10th - 12th Grade

Practice Problem

Medium

CCSS
HSA.CED.A.2, HSA.SSE.B.3, HSF.IF.B.4

+6

Standards-aligned

Created by

Rachel Meier

Used 141+ times

FREE Resource

6 Slides • 11 Questions

1

3.1 Writing Quadratic Equations

Have your notebook nearby to show your work!

Slide image

2

Forms of Quadratic Functions

  • Vertex Form:  

     y=a(xc)2+dy=a\left(x-c\right)^2+d  

  • Standard Form:       y=ax2+bx+cy=ax^2+bx+c  

  • Root Form:  y=x(xr1)(xr2)y=x\left(x-r_1\right)\left(x-r_2\right)  

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3

Multiple Choice

What form of a quadratic is given?

 f(x)=2x2+3x4f\left(x\right)=2x^2+3x-4  

1

Vertex Form

2

Standard Form

3

Root Form

4

Multiple Choice

What form of a quadratic is given?

 f(x)=3(x2)2+4f\left(x\right)=3\left(x-2\right)^2+4  

1

Vertex Form

2

Standard Form

3

Root Form

5

Multiple Choice

What form of a quadratic is given?

 f(x)=(x+2)(x5)f\left(x\right)=-\left(x+2\right)\left(x-5\right)  

1

Vertex Form

2

Standard Form

3

Root Form

6


7

Multiple Choice

Find the equation for a parabola that has a vertex at (3, 4) and goes through the point (2, 2).

1

y=(x3)2+4y=\left(x-3\right)^2+4

2

y=225(x+3)2+4y=-\frac{2}{25}\left(x+3\right)^2+4

3

y=2(x3)2+4y=-2\left(x-3\right)^2+4

4

y=2(x+3)24y=-2\left(x+3\right)^2-4

8

Multiple Choice

Lets do another problem just to make sure we've got this.



Find the equation of a parabola that has a vertex at (2, -7) and goes through the point (3, -4).

1

y=325(x+2)27y=\frac{3}{25}\left(x+2\right)^2-7

2

y=3(x2)27y=3\left(x-2\right)^2-7

3

y=3(x+2)27y=3\left(x+2\right)^2-7

4

y=(x2)27y=\left(x-2\right)^2-7

9

Fill in the Blank

Type answer...

10

11

Multiple Choice

Write the equation for a parabola that has the roots x=2 and x=4 and goes through the point (0, -4).

1

y=12(x+2)(x+4)y=-\frac{1}{2}\left(x+2\right)\left(x+4\right)

2

y=12(x2)(x4)y=-\frac{1}{2}\left(x-2\right)\left(x-4\right)

3

y=(x2)(x4)y=\left(x-2\right)\left(x-4\right)

4

y=12(x2)(x3)y=-\frac{1}{2}\left(x-2\right)\left(x-3\right)

12

Multiple Choice

Lets do another one just to make sure we get this down.


Write the equation for a parabola that has the roots x=-3 and x=1 and goes through the point (-2, -9).

1

 y=3(x3)(x+1)y=3\left(x-3\right)\left(x+1\right) 

2

 y=(x+3)(x1)y=\left(x+3\right)\left(x-1\right) 

3

 y=(x3)(x+1)y=\left(x-3\right)\left(x+1\right) 

4

 y=3(x+3)(x1)y=3\left(x+3\right)\left(x-1\right) 

13

Multiple Select

Given the equation

 f(x)=2(x4)(x+6)f\left(x\right)=2\left(x-4\right)\left(x+6\right) , determine the roots (zeros) for this parabola.

Select all that apply.

1

x = -6

2

x = -4

3

x = 2

4

x = 4

5

x = 6

14

15

Multiple Choice

Write the equation of a parabola that goes through (-2, 3), (-1, 0), and (1, 6).

1

y=x2+2x+3y=x^2+2x+3

2

y=2x2+3x+1y=2x^2+3x+1

3

y=3x2+3xy=3x^2+3x

4

y=3x2+2x+3y=3x^2+2x+3

16

Multiple Choice

Alright, one more time. 


Write the equation of a parabola that goes through (7, -4), (5, -1), and (1, -1).

1

 y=0.25x2+15x+2.25y=-0.25x^2+15x+2.25 

2

 y=0.25x21.5x+2.25y=0.25x^2-1.5x+2.25 

3

 y=0.25x2+1.5x2.25y=-0.25x^2+1.5x-2.25 

4

 y=x2+x2y=-x^2+x-2 

17

This is for a grade! You must make a 70 on this lesson to receive credit.

At the end of the unit, I will see what lessons you have completed. If you completed all of them, it's an easy 100 for a quiz.

3.1 Writing Quadratic Equations

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