Writing Equations

Writing Equations

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Multiple Choice

Company A charges a one-time installation fee of $40 and then $4 per month. Company B charges a one-time installation fee of $24 and then $6 per month. After how many months will a person using Company A pay the same as a person using company B?

• 40 - 4x = 24 - 6x

• 40x + 4 = 24x + 6

• 40 + 4x = 24 - 6x

• 40 + 4x = 24 + 6x

Multiple Choice

The Red Bus Company's charges $150 plus $72 each hour to rent a bus. The Blue Bus Company's charges $240 plus $54 each hour to rent a bus. Write an equation to show for how many hours would the companies charge the same.

• 150 - 72x = 240 - 54x

• 150 + 72x = 240 + 54x

• 150 + 72x = 240 - 54x

• 150x + 72 = 240x + 54

Multiple Choice

The temperature in your town is 21° and rising 1.5°every hour. Your friend lives far away and the temperature is 28° and falling 2° every hour. In how many hours will the temperature be equal?

• 21 + 1.5h = 28 + 2h

• 21 + 1.5h = 28 - 2h

• 1.5 + 21h = 2 + 28h

• 21 - 1.5h = 28 - 2h

Multiple Choice

The price of stock A at 9 AM is $12.73.  Since then, the price has been increasing at the rate of $0.06 each hour.  At noon the price of stock B was $13.48.  It begins to decrease at the rate of $0.14 each hour.  If the two rates continue, in how many hours will the prices of the two stocks be the same?

• 12.73x + .06 = 13.48x - 0.14

• 12.73 + .06x = 13.48 - 0.14x

• 12.73 - .06x = 13.48 - 0.14x

• 12.73 + .06x = 13.48 + 0.14x

Multiple Choice

A town's population is 14,000, and it is increasing by 160 people every year. A nearby town has a population of 24,000, and it is decreasing by 200 people every year. In about how many years will the populations of the towns be equal?

• 14,000 + 160y = 24,000 - 200y

• 14,000 + 160y = 24,000 + 200y

• 14,000y + 160 = 24,000y - 200

• 14,000 - 160y = 24,000 - 200y