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Conic Sections

Conic Sections

Assessment

Presentation

•

Mathematics

•

10th - 12th Grade

•

Medium

•
CCSS
HSG.GPE.A.1, HSG.GPE.A.2

Standards-aligned

Created by

Sandra Yoder

Used 17+ times

FREE Resource

1 Slide • 29 Questions

1

Conic Sections

Practice identifying characteristics of conic sections from graphs and equations

media

2

Multiple Choice

A hyperbola centered at (-3, 2) with a horizontal tranverse axis has asymptotes y = ± ¾x. Which of the following could be the equation of the hyperbola in standard form?

1

(x+3)216+(y−2)29=1\frac{\left(x+3\right)^2}{16}+\frac{\left(y-2\right)^2}{9}=1

2

(y−2)29−(x+3)216−=1\frac{\left(y-2\right)^2}{9}-\frac{\left(x+3\right)^2}{16}-=1

3

(x+3)216−(y−2)29=1\frac{\left(x+3\right)^2}{16}-\frac{\left(y-2\right)^2}{9}=1

4

(x+3)29−(y−2)216=1\frac{\left(x+3\right)^2}{9}-\frac{\left(y-2\right)^2}{16}=1

3

Multiple Choice

Write the standard form of the Hyperbola that has vertices at (0, 13) and (0, -15) and asymptotes at y=75x−1y=\frac{7}{5}x-1  and  y=−75x−1y=-\frac{7}{5}x-1 . 

1

(y+1)2196−x2100=1\frac{\left(y+1\right)^2}{196}-\frac{x^2}{100}=1  

2

y2196−(x−1)2100=1\frac{y^2}{196}-\frac{\left(x-1\right)^2}{100}=1  

3

x2100−(y−1)2196=1\frac{x^2}{100}-\frac{\left(y-1\right)^2}{196}=1  

4

x2196−(y+1)2100=1\frac{x^2}{196}-\frac{\left(y+1\right)^2}{100}=1  

4

Multiple Choice

Question image

Find the equation of hyperbola.

1

(x−2)216−(y+3)220=1\frac{\left(x-2\right)^2}{16}-\frac{\left(y+3\right)^2}{20}=1

2

(x+3)216−(y−2)220=1\frac{\left(x+3\right)^2}{16}-\frac{\left(y-2\right)^2}{20}=1

3

(x−2)220−(y+3)216=1\frac{\left(x-2\right)^2}{20}-\frac{\left(y+3\right)^2}{16}=1

4

(y+3)216−(x−2)220=1\frac{\left(y+3\right)^2}{16}-\frac{\left(x-2\right)^2}{20}=1

5

Multiple Choice

Find the standard form of the Hyperbola given that 25x2−4y2−250x+16y+209=025x^2-4y^2-250x+16y+209=0 . 

1

(x−5)216−(y−2)2=1\frac{\left(x-5\right)^2}{16}-\left(y-2\right)^2=1  

2

(y−2)2100−(x−5)216=1\frac{\left(y-2\right)^2}{100}-\frac{\left(x-5\right)^2}{16}=1  

3

(x−5)216−(y−2)2100=1\frac{\left(x-5\right)^2}{16}-\frac{\left(y-2\right)^2}{100}=1  

4

(x−5)2100−(y−2)216=1\frac{\left(x-5\right)^2}{100}-\frac{\left(y-2\right)^2}{16}=1  

6

Multiple Choice

Identify the asymptotes of the equation: (y−1)264−(x+9)236=1\frac{\left(y-1\right)^2}{64}-\frac{\left(x+9\right)^2}{36}=1  

1

y=43x + 13  ; y=−43x − 11y=\frac{4}{3}x\ +\ 13\ \ ;\ y=-\frac{4}{3}x\ -\ 11  

2

y=43x + 233 ; y=−43x + 313y=\frac{4}{3}x\ +\ \frac{23}{3}\ ;\ y=-\frac{4}{3}x\ +\ \frac{31}{3}  

3

y=34x + 314 ; y=−34x − 234y=\frac{3}{4}x\ +\ \frac{31}{4}\ ;\ y=-\frac{3}{4}x\ -\ \frac{23}{4}  

4

y=43x − 233 ;  y=−43x − 313y=\frac{4}{3}x\ -\ \frac{23}{3}\ ;\ \ y=-\frac{4}{3}x\ -\ \frac{31}{3}  

7

Multiple Choice

Question image

What are the coordinates of the Foci ?

1

(−16,2),(10,2)\left(-16,2\right),\left(10,2\right)

2

(−15,2),(9,2)\left(-15,2\right),\left(9,2\right)

3

(−3,15),(−3,−11)\left(-3,15\right),\left(-3,-11\right)

4

(15,−2),(−9,−2)\left(15,-2\right),\left(-9,-2\right)

8

Multiple Choice

What are the foci of the hyperbola with the equation  y212−x25=1\frac{y^2}{12}-\frac{x^2}{5}=1 .

1

(0,±17)\left(0,\pm\sqrt{17}\right)  

2

(±17,0)\left(\pm\sqrt{17},0\right)  

3

(0,±7)\left(0,\pm\sqrt{7}\right)

4

(±7,0)\left(\pm\sqrt{7},0\right)  

9

Multiple Choice

Question image

What are the co-vertices of the ellipse?

1

(−5,3)\left(-5,3\right)

2

(−5,0) and (−5,6)\left(-5,0\right)\ and\ \left(-5,6\right)

3

(3,−5)\left(3,-5\right)

4

(−10,3) and (0,3)\left(-10,3\right)\ and\ \left(0,3\right)

10

Multiple Choice

Which of the following is the graph of  (x+3)24+(y+1)29=1\frac{\left(x+3\right)^2}{4}+\frac{\left(y+1\right)^2}{9}=1  

1
2
3
4

11

Multiple Choice

Question image

Find the standard equation of the given ellipse

1
2
3
4

12

Multiple Choice

Determine the center and foci of an ellipse 4x2+y2−16x−10y+25=04x^2+y^2-16x-10y+25=0  

1

Center (-2,3) and foci =  (5, 3±2)\left(5,\ 3\pm\sqrt{2}\right)  

2

Center (4,-6) and foci =  (2, 3±4)\left(2,\ 3\pm\sqrt{4}\right)  

3

Center (2, 5) and foci =  (2, 5±12)\left(2,\ 5\pm\sqrt{12}\right)  

4

Center (3,-2) and foci=  (5, 2±12)\left(5,\ 2\pm\sqrt{12}\right)  

13

Multiple Choice

The focus is at (2,0) and the vertex is at (-4,0). What is the equation of the parabola?

1

y2=24(x+4)y^2=24\left(x+4\right)

2

(y+4)2=−12x\left(y+4\right)^2=-12x

3

x2=16(y+4)x^2=16\left(y+4\right)

4

(x+4)2=−20y\left(x+4\right)^2=-20y

14

Multiple Choice

(x+3)2 = 4(y+5)

What is the equation of the directrix?

1

x=4x=4


2

x=2x=2

3

y=−4y=-4

4

y=−5y=-5

15

Multiple Choice

What are the coordinates for the focus?

(y−4)2=−8(x+1)\left(y-4\right)^2=-8\left(x+1\right)  

1

(1,4)\left(1,4\right)  

2

(1,−6)\left(1,-6\right)

3

(1,−2)\left(1,-2\right)  

4

(−3,4)\left(-3,4\right)

16

Multiple Choice

What direction does this parabola open?

(y−4)2=−8(x+1)\left(y-4\right)^2=-8\left(x+1\right)  

1

up

2

down

3

left

4

right

17

Multiple Choice

All parabolas with a vertical directrix open the left or right.

1

true

2

false

18

Multiple Choice

Given the equation of the parabola,  y2−16y+8x−15=0y^2-16y+8x-15=0 where would the VERTEX be? 

1

 (3,3)\left(3,3\right)  


2

 (24,3)\left(24,3\right)  

3

 (−24,3)\left(-24,3\right)  

4

 (−3,3)\left(-3,3\right)  (-3, 3)

19

Multiple Choice

(y−9)2=−40(x+4)\left(y-9\right)^2=-40\left(x+4\right)  

What direction does the parabola open?

1

Up

2

Down

3

Left

4

Right

20

Multiple Choice

Write an equation for the ellipse with each set of characteristics. Then answer the question. Vertices (−2,−4),(−2,8)\left(-2,-4\right),\left(-2,8\right)   Length of minor axis is 10 What is the center of the ellipse?

1

(−2,2)\left(-2,2\right)

2

(−2,4)\left(-2,4\right)

3

(2,−2)\left(2,-2\right)  

4

(−2,1)\left(-2,1\right)

21

Multiple Choice

(y+5)2=−12(x−2)\left(y+5\right)^2=-12\left(x-2\right)  

What is the focus of the  parabola?

1

(2, - 5)

2

( -5, 2)

3

(1 , -5 )

4

(-1, -5 )

22

Multiple Choice

(x−4)2=8(y+3)\left(x-4\right)^2=8\left(y+3\right)  

What is the directrix of the parabola?

1

y = - 3

2

x= 5

3

y= - 5

4

y= 2

23

Multiple Choice

Question image

Which type of conic section is this equation?

1

circle

2

ellipse

3

hyperbola

4

parabola

24

Multiple Choice

Question image

Which type of conic section is this equation?

1

circle

2

ellipse

3

hyperbola

4

parabola

25

Multiple Choice

Question image

Which type of conic section is this equation?

1

circle

2

ellipse

3

hyperbola

4

parabola

26

Multiple Choice

Question image

Which type of conic section is this equation?

1

circle

2

ellipse

3

hyperbola

4

parabola

27

Multiple Choice

Question image

Which type of conic section is this equation?

1

circle

2

ellipse

3

hyperbola

4

parabola

28

Fill in the Blanks

A

Type answer...

is the set of all points equidistant from a focus and a line called the directrix.

29

Fill in the Blanks

An

Type answer...

is the set of all points such that the distances between a point on the curve and its foci have a constant sum.

30

Fill in the Blanks

The difference of the distances between a point on a curve and its foci is a constant is the definition of a(n)

Type answer...

pattern-tertiary
Conic Sections

Practice identifying characteristics of conic sections from graphs and equations

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