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Factoring and solving quadratics

Factoring and solving quadratics

Assessment

Presentation

Mathematics

9th - 12th Grade

Practice Problem

Medium

CCSS
HSA.SSE.A.2, HSA-REI.B.4B, HSA.REI.B.4

+5

Standards-aligned

Created by

Melissa Morgan

Used 19+ times

FREE Resource

5 Slides • 18 Questions

1

Factoring and solving quadratics

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2

Factoring

1) Look for a GCF


3

Multiple Choice

What is the GCF of 18k and 15k3
1
3k2
2
3k3
3
3k
4
5k

4

Multiple Choice

Factor:

2n2-8n3

1

2n2(n-4n2)

2

-2n2(4n2-1)

3

2n3(10-8n2)

4

3n(1-4n)

5

Multiple Choice

Factor:
10a4+16a+10a2
1
2a(5a3+8+5a)
2
2a4(5a+8a2+5a3)
3
2a4(10+16a+40a2)
4
3a3(5+8a+a2)

6


  • If you have 3 terms use the X method

  • If there is a number in front of your squared term, slide and divide

7

Multiple Choice

x2 - 9x - 22

1

(x + 11) (x - 2)

2

(x + 2) (x - 11)

3

(x - 11) (x - 2)

4

(x + 2) (x + 11)

8

Multiple Choice

x2 - 9x + 18

1

(x + 6) (x + 3)

2

(x - 6) (x - 3)

3

(x - 2) (x - 9)

4

(x + 2) (x + 9)

9

Multiple Choice

x2 + 5x + 6

1

(x - 3) (x - 2)

2

(x + 3) (x - 2)

3

(x + 3) (x + 2)

4

(x + 2) (x - 3)

10

Multiple Choice

x2 + 8x - 20

1

(x + 10) (x - 2)

2

(x + 10) (x + 2)

3

(x + 5) (x + 4)

4

(x + 5) (x - 4)

11

Multiple Choice

7x2 - 16x + 4

1

(x + 2) (7x - 2)

2

(x + 2) (7x + 2)

3

(x - 2) (7x + 2)

4

(x - 2) (7x - 2)

12

Multiple Choice

6x2 - x - 1

1

(3x - 1) (2x + 1)

2

(3x + 1) (2x - 1)

3

(6x + 1) (x - 1)

4

(6x - 1) (x + 1)

13

Multiple Choice

3x2 + 8x + 5

1

(x - 1) (3x - 5)

2

(3x - 1) (x - 5)

3

(x + 1) (3x + 5)

4

(3x + 1) (x + 5)

14

To solve by factoring

  • Use the box method to factor.- make sure everything is on one side and set = 0

  • Set each factor = 0 and solve

15

Multiple Choice

 n210n+24=0n^2-10n+24=0  

1

 {8,3}\left\{8,3\right\}  

2

 {4,6}\left\{4,6\right\}  

3

 {4,6}\left\{-4,-6\right\}  

4

 {12,2}\left\{12,2\right\}  

16

Multiple Choice

 b2+8b33=0b^2+8b-33=0  

1

 {8,33}\left\{8,-33\right\}  

2

 {3,11}\left\{3,-11\right\}  

3

 {3,11}\left\{3,11\right\}  

4

 {11,3}\left\{-11,-3\right\}  

17

Multiple Choice

 x224x+114=19x^2-24x+114=19  

1

 {10,14}\left\{10,14\right\}  

2

 {5,19}\left\{-5,-19\right\}  

3

 {24, 19}\left\{24,\ 19\right\}  

4

 {5,19}\left\{5,19\right\}  

18

Quadratic Formula

  • Make sure your equation is set = 0 and find a, b and c

  • Use the formula:

     x = (b)±(b)24(a)(c)2(a)x\ =\ \frac{-\left(b\right)\pm\sqrt{\left(b\right)^2-4\left(a\right)\left(c\right)}}{2\left(a\right)}  

19

Multiple Choice

What should you do first in solving this equation?

x2 + 6x - 13 = 3

1

Factor

2

Write down: a = 1, b = 6, c = -13

3

Subtract 3 from both sides.

4

Add 3 to both sides.

20

Multiple Choice

Determine the values of a, b, and c for the quadratic equation:

4x2 – 8x = 3

1

a = 4, b = -8, c = 3

2

a = 4, b =-8, c =-3

3

a = 4, b = 8, c = 3

4

a = 4, b = 8, c = -3

21

Multiple Choice

Solve using the Quadratic Formula:

2x2 + x - 4 = 0

1

x = -¼ and x = -2

2

x = 1.19 and x = -1.69

3

x = 8 and x = -4

4

x = 1.69 and x = 1.20

22

Multiple Choice

Solve 2x2 + 7x - 15 = 0

1

-3/2 or 5

2

No Solution

3

-5 or 3/2

4

0.7 or 5

23

Multiple Choice

Use the quadratic formula to solve 2x2 + 2x - 12.

1

-2, 3

2

2, 3

3

2, -3

4

-2, -3

Factoring and solving quadratics

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