3-4 Factoring Polynomials - Part 1

3-4 Factoring Polynomials - Part 1

3-4 Notes Part 1 - factoring polynomials

Multiple Choice

If one number is divisible by another, what should be the remainder if you were to divide them?

• 1

• 0

• undefined

• 2

This also applies when dividing polynomials!

(yeah!)

Multiple Select

How can you tell if (x-5) is a factor of x³-125? Select all that apply.

• Divide. If the remainder is 0 then (x-5) is a factor.

• Divide. If the remainder is 1 then (x-5) is a factor.

• Use the remainder theorem by plugging in 5. If the remainder is 0 then (x-5) is a factor.

• Use the remainder theorem by plugging in -5. If the remainder if 0 then (x-5) is a factor.

Multiple Choice

Is (x-5) a factor of x³-125?

• Yes

• No

We can use division to factor polynomials of higher degrees

In the previous example, (x³-125)÷(x-5) = x²+5x+25.

Working backwards, that means multiplying (x²+5x+25) and (x-5) is equal to x³-125.

If x²+5x+25 was factorable, we would keep factoring.

Since it's not, the expression is factored completely.

Multiple Choice

One factor is x-3. Find the other factor of
  

 $p\left(x\right)\ =\ x^3+2x^2-13x-6$  

•  $x^3-x^2-10x+24$  

•  $x^2−x−10+\frac{24}{x-3}$  

•  $x^3+5x^2+2x$  

•  $x^2+5x+2$  

Since you were told x-3 is a factor, you know the remainder has to be 0. If it isn't, you made a mistake somewhere.

Woops!

Multiple Choice

Select the factored form of

 $p\left(x\right)=x^3+2x^2-13x-6$  

•  $(x−3)(x^3−x^2−10x+24)$  

•  $(x−3)(x^3+5x^2+2x)$  

•  $\left(x-3\right)\left(x^2-x-10+\frac{24}{x-3}\right)$  

•  $(x−3)(x^2+5x+2)$  

Fill in the Blanks

Review:

Factor. Type your answer with NO SPACES.

x²-8x-20

Multiple Select

Review:

Now solve by factoring.

x²-8x-20=0

• 10

• 2

• -2

• -10

Remember, to solve by factoring, set each factor equal to 0 and solve for x.

• x-10=0
• Add 10 to get x=10
• x+2=0
• Subtract 2 to get x=-2

Read this problem. I will go through it one step at a time.

Multiple Choice

What year will the pond dry up?

• 2016

• 2010

• 2030

• 2006

The problem states that the water level of the pond has been measured since 2006. That means the y-intercept is the water level in 2006. The pond's depth reaches 0 feet at an x-value of 10. Since x is years, 10 years since 2006 would be the year 2016.

It actually is fun!

That means we can divide x³-16x²+74x-140 by x-10 and get a remainder of 0.

Multiple Choice

 Use synthetic division to divide$\left(x^3-16x^2+74x-140\right)\div\left(x-10\right)$  

•  $x^2−6x+14$  

•  $x^3−6x^2+14x$  

•  $x^2−26x+334-\frac{3480}{x-10}$  

•  $x^2-26x+334-\frac{3480}{x+10}$  

This is the fully factored form of d(x)

The amount of voters on a single day is represented by the graph, where x is hours and y is number of voters.

We can tell a lot about this scenario just by looking at the graph.

Approximately how many voters arrived when the voting location opened? Go to the next slide to answer.

Multiple Choice

Approximately how many voters arrived when the voting location opened?

• 56

• 8

• 4

• 26

Since we can't have negative time, 0 hours is when the voting location opens. The y-value is 56.

Approximately how many voters were there 2.6 hours after opening? Go to the next slide to answer.

Multiple Choice

Approximately how many voters were there 2.6 hours after opening?

• 10

• 26

• 4

• 34

About 2.6 hours, the y-value is approximately 4.

How long is this polling place open? Go to the next slide to answer.

Multiple Choice

How long is this polling place open?

• 8 hours

• 6.1 horus

• 2.6 hours

• 4.7 hours

The number of people becomes negative after 8 hours, which doesn't make sense.

The equation of the graph is   undefined 

Multiple Choice

$$p\left(x\right)=-x^3+13x^2-47x+56$$  Use the graph to factor p(x)

• $$(x^2−5x+7)(x−8)$$  

• $$−1(x^2−5x+7)(x−8)$$  

• $$−1(x+8)\left(−x^3+21x^2−215\right)$$  

• $$-1\left(x+8\right)(x^2+21x−215)$$  

Make sure you also complete 3-4 Notes Part 2!