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Unit 3 Test Review

Unit 3 Test Review

Assessment

Presentation

Mathematics

9th - 12th Grade

Medium

CCSS
HSG.SRT.C.6, HSG.SRT.C.8, HSF.TF.B.7

Standards-aligned

Created by

Erica Guevara

Used 11+ times

FREE Resource

4 Slides • 15 Questions

1

Unit 3 Test Review

Trigonometry & Inverse Trig

Test on Wednesday 9/29

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2

Labeling Opposite, Adjacent & Hypotenuse

3

Multiple Choice

Question image

The side labeled 9 is called the ________.

1

Opposite

2

Adjacent

3

Hypotenuse

4

Multiple Choice

Question image

The side labeled x is called the ________.

1

Opposite

2

Adjacent

3

Hypotenuse

5

Multiple Choice

Question image

We would write a _______ equation to solve this triangle for x.

1

Sine

2

Cosine

3

Tangent

6

Multiple Choice

Question image

The side labeled 10 is called the ________.

1

opposite

2

adjacent

3

hypotenuse

7

Multiple Choice

Question image

The side labeled x is called the ________.

1

opposite

2

adjacent

3

hypotenuse

8

Multiple Choice

Question image

We would write a _______ equation to solve this triangle for x.

1

Sine

2

Cosine

3

Tangent

9

Multiple Choice

Question image

The side labeled 2 is called the ________.

1

opposite

2

adjacent

3

hypotenuse

10

Multiple Choice

Question image

The side labeled x is called the ________.

1

opposite

2

adjacent

3

hypotenuse

11

Multiple Choice

Question image

We would write a _______ equation to solve this triangle for x.

1

Sine

2

Cosine

3

Tangent

12

Regular Trigonometry is used to

Solve for a missing side!

13

Multiple Choice

Question image

Trigonometry: 

Which of the following is the correct setup to solve for AC?

1

cos(27°)=8AC\cos\left(27\degree\right)=\frac{8}{AC}  

2

cos(27°)=AC8\cos\left(27\degree\right)=\frac{AC}{8}  

3

sin(27°)=8AC\sin\left(27\degree\right)=\frac{8}{AC}

4

sin(27°)=AC8\sin\left(27\degree\right)=\frac{AC}{8}

14

Multiple Choice

Trigonometry:

 Solve the equation  sin(27°)=8AC\sin\left(27\degree\right)=\frac{8}{AC}  

Round to the nearest tenth.

1

3.6

2

9

3

17.6

4

7.1

5

0.6

15

Multiple Choice

Question image

Trigonometry: 

Which of the following is the correct setup to solve for x?

1

tan(43°)=12x\tan\left(43\degree\right)=\frac{12}{x}

2

tan(43°)=x12\tan\left(43\degree\right)=\frac{x}{12}

3

sin(43°)=12x\sin\left(43\degree\right)=\frac{12}{x}

4

sin(43°)=x12\sin\left(43\degree\right)=\frac{x}{12}

16

Multiple Choice

Trigonometry:

 Solve the equation  tan(43°)=x12\tan\left(43\degree\right)=\frac{x}{12}  

Round to the nearest tenth.

1

11.2

2

12.9

3

0.28

4

0.9

17

Inverse-1 Trigonometry is used to

Solve for a missing side!

18

Multiple Choice

Question image

Inverse Trigonometry: 

Solve for measure of  A\angle A

Round to the  nearest Degree.

1

Type in sin1(1227)\sin^{-1}\left(\frac{12}{27}\right) to DESMOS and you get  26°26\degree  

2

Type in sin1(2712)\sin^{-1}\left(\frac{27}{12}\right) to DESMOS and you get undefined.

3

Type in cos1(1227)\cos^{-1}\left(\frac{12}{27}\right) to DESMOS to get  64°64\degree  

4

Type in cos1(2712)\cos^{-1}\left(\frac{27}{12}\right) to DESMOS to get undefined.

19

Multiple Choice

Question image

Inverse Trigonometry: 

Solve for measure of  B\angle B

Round to the  nearest Degree.

1

Type in sin1(1636)\sin^{-1}\left(\frac{16}{36}\right) to DESMOS and you get  26°26\degree  

2

Type in sin1(3616)\sin^{-1}\left(\frac{36}{16}\right) to DESMOS and you get undefined.

3

Type in cos1(1636)\cos^{-1}\left(\frac{16}{36}\right) to DESMOS to get  64°64\degree  

4

Type in tan1(1636)\tan^{-1}\left(\frac{16}{36}\right) to DESMOS to get 24°24\degree  .

Unit 3 Test Review

Trigonometry & Inverse Trig

Test on Wednesday 9/29

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