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Chapter 11 ICP

Chapter 11 ICP

Assessment

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Science

KG

Hard

Created by

Natalie Lenard

Used 3+ times

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3 Slides • 0 Questions

1

"Redox Tower"

Electrons donated by the “half-reactions” on top can be consumed in a half-reaction lower on the tower to complete a thermodynamically favorable reaction. Since the oxidation of glucose lies at the top of the tower and the reduction of NAD+ is below it, this electron flow is thermodynamically favorable. We can see that this is favorable to generate ATP (bottom).

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2

Standard Reduction Potential

Use the table to (A) write out the balanced reaction between NADH and water and (B) to compute the standard reduction potential for it.

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3

Answer

1/2O2 + 2H+ + 2e' → H2O; e0' = 0.816 volts

NAD+ + 2H+ + 2e' → NADH + H+ ; e0' = -0.320 volts

Δe0' = e0'(what gets reduced) - e0'(what gets oxidized)

Δe0' = 0.816 - (-0.320) = +1.14 volts


Equivalent to approximately -220 kJ/mol and can drive the formation of several ATP molecules.


"Redox Tower"

Electrons donated by the “half-reactions” on top can be consumed in a half-reaction lower on the tower to complete a thermodynamically favorable reaction. Since the oxidation of glucose lies at the top of the tower and the reduction of NAD+ is below it, this electron flow is thermodynamically favorable. We can see that this is favorable to generate ATP (bottom).

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