Horizontal Projectile Motion

Horizontal Projectile Motion

Multiple Choice

Which is newtons first law states

• An object at rest will remain at rest unless a force is applied

• An object is moving

• An object has stopped

• An moving object will keep going when a force is applied to it

X component acceleration

the object has no other forces acting on it

velocity is constant

a=0

X component velocity

v_ix velocity in the x direction

is equal to the original velocity

Multiple Choice

How can you describe the motion on the horizontal axis if you ignore air resistance?

• acceleration due to gravity
• constant velocity
• varying acceleration
• motionless

Multiple Choice

Acceleration in the x direction is

• 9.8

• 0

• not enough information

• =mg

X component Displacement

 $\Delta x=v_it+\frac{1}{2}at^2$   $a=0$  
 $\Delta x=v_{i_{ }}t$  

X direction

 $v_{ix\ }\ or\ v_{ox_{\ }}\ =\ the\ intial\ velocity$ 

y component acceleration

• a_y=acceleration due to gravity

• a_y=9.8

Multiple Choice

The acceleration in the y direction is due to

• mass

• weight

• gravity

Multiple Choice

An object is pushed off a ledge the initial velocity in the downward direction (y) is

• 0

• 9.8

• depends on the mass

• v_o

y component velocity

• v_fy=v_iy+at

• v_iy=0

• v_fy=gt

y component displacement

  $\Delta y=v_{i_{ }}t+\frac{1}{2}gt^2$ 

  $y_{f_{ }}=h+\frac{1}{2}gt^2$ 

 

Y displacement

y_i=height

the object returns to origin along the y axis

y_f=0

Time in both x and y direction is the same

solving time y direction

•  $h=\frac{1}{2}gt^2$  

•  $t=\sqrt{\frac{2h}{g}}$  

Solving x displacement

•  $\Delta x=v_{i_{ }}t$  

•  $\Delta x=v_{i_{ }}\sqrt{\frac{2h}{g}}$  

final velocity with regards to both x and y components

•  $t=\sqrt{\frac{2h}{g}}$  

•  $v=\sqrt{v_i^2+g^{ }2h}$