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Solving Proportions using Cross Multiply and Divide

Solving Proportions using Cross Multiply and Divide

Assessment

Presentation

•

Mathematics

•

7th - 10th Grade

•

Practice Problem

•

Medium

•
CCSS
7.RP.A.2B, 7.RP.A.3, 6.EE.B.7

+1

Standards-aligned

Created by

Kelly Rubel

Used 41+ times

FREE Resource

5 Slides • 8 Questions

1

Solving Proportions using Cross Multiply and Divide

I can get ready for Similarity!

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2

Why does the cross multiply and divide method work?

It's kind of like creating equivalent fractions.

3

4

Multiple Choice

What is the first step in using the cross multiply and divide method to solve this proportion?

 k4=38\frac{k}{4}=\frac{3}{8}  

1

 4k=3⋅84k=3\cdot8  

2

 3⋅4=8⋅k3\cdot4=8\cdot k  

5

Multiple Select

Solve this proportion:

 k3=48\frac{k}{3}=\frac{4}{8}  

1

 k=1.5k=1.5  

2

 k=128k=\frac{12}{8}  

3

 k=323k=\frac{32}{3}  

4

 k=6k=6  

6

Multiple Choice

Solve this proportion:

 z7=2428\frac{z}{7}=\frac{24}{28}  

1

z=6

2

z=11

3

z=4

4

z=168

7

Multiple Choice

Solve this proportion:

 n10=4.75\frac{n}{10}=\frac{4.7}{5}  

1

n=2

2

n=9.4

3

n=2.35

4

n=0.5

8

Open Ended

How is this problem different? How do you think the steps for solving will change?





 (x−1)2=128\frac{\left(x-1\right)}{2}=\frac{12}{8}  

9

10

Multiple Choice

 125=5n\frac{12}{5}=\frac{5}{n}  

1

 n=12n=12  

2

 n=2512n=\frac{25}{12}  

11

Multiple Choice

 73=4t\frac{7}{3}=\frac{4}{t}  

1

 t=127t=\frac{12}{7}  

2

 t=283t=\frac{28}{3}  

3

 t=1.7t=1.7  

4

 t=9.3t=9.3  

12

Multiple Choice

 10.8d=610\frac{10.8}{d}=\frac{6}{10}  

1

 d=6.48d=6.48  

2

 d=5.5d=5.5  

3

 d=18d=18  

13

IXL, Algebra I, C.5

https://www.ixl.com/math/algebra-1/solve-proportions


Get it as high as you can by the end of class!

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Solving Proportions using Cross Multiply and Divide

I can get ready for Similarity!

media

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