Solving Square Root Functions

Solving Square Root Functions

Extraneous Solutions

• A solution that gives you an expression that is not true

• extraneous = extraño = strange

Factoring review

• Steps to factoring trinomials with the form

   $ax^2+bx+c$  

• 1. Find  $A\cdot C$                                                                                            2. Find factors of   $A\cdot C$  using a T - Chart                                            3. Decide which two factors add up to B                                                  4. Fill in the Box and Factor out the GCF                                               5. Answer will be two binomials

Open Ended

What are the factors of the following expression?
 $0=x^2+3x-28$  

Multiple Choice

 $\sqrt{x}-4=6$  

•  $x=52$  

•  $x=100$  

•  $x=4$  

•  $x=10$  

Multiple Choice

 $\sqrt{x+7}-5=x$  

• x = -3, -6 (extraneous) 

• x= -6, -3 (extraneuous) 

• x = -6, -3

• x = -2 , -3

Multiple Choice

 $x+4=\sqrt{x+10}$  

• x = -1 , -6 (extreneous)

• x = -6, -1 (extraneous) 

• x = -2, -1 (extraneous)

• x = -1, -6

Multiple Choice

 $\sqrt{x-5}=-2$  

• x=9 ( extreneous) 

• x=8

• x=3 ( extraneous) 

• x=6 ( extrenaous) 

Multiple Choice

 $\sqrt{x+4}=x-2$  

• x= 0, 5 (extraneuous) 

• x= 2, 7

• x= 5, 0 

• x= 3, 9