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Change of Base Rule

Change of Base Rule

Assessment

Presentation

•

Mathematics

•

9th - 12th Grade

•

Practice Problem

•

Medium

Created by

Beth Knott

Used 23+ times

FREE Resource

8 Slides • 6 Questions

1

Change of Base Rule

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Evaluate the logarithm. Round your answer to the nearest thousandth. (3 decimal places)

  •  log⁡345\log_345 

  • We cannot write 3 to some exponent and get 45 so the change of base formula is appropriate.

  • By the change of base rule  log⁡345=log⁡45log⁡3\log_345=\frac{\log45}{\log3}  

  •  ≈3.465\approx3.465  

  • Some calculators have the ability to do this without using the change of base. You need to know this as a property of logarithms for upcoming work.

4

Multiple Choice

Evaluate the logarithm. Round your answer to the nearest thousandth. (3 decimal places)

 log⁡8200\log_8200  

1

 log⁡8200=log⁡200log⁡8≈2.548\log_8200=\frac{\log200}{\log8}\approx2.548  

2

 log⁡8200=log⁡8log⁡200≈.392\log_8200=\frac{\log8}{\log200}\approx.392  

5

Evaluate the logarithm. Round your answer to the nearest thousandth. (3 decimal places)

  •  5log⁡12515\log_{12}51  

  •  =5(log⁡51log⁡12)=5\left(\frac{\log51}{\log12}\right)  

  •  ≈7.911\approx7.911  

6

Multiple Choice

Evaluate the logarithm. Round your answer to the nearest thousandth. (3 decimal places)

 log⁡4(1100)\log_4\left(\frac{1}{100}\right)  

1

 log⁡(1100)log⁡4≈3.322\frac{\log\left(\frac{1}{100}\right)}{\log4}\approx3.322  

2

 log⁡(1100)log⁡4≈−3.322\frac{\log\left(\frac{1}{100}\right)}{\log4}\approx-3.322  

3

 log⁡4log⁡(1100)≈−.301\frac{\log4}{\log\left(\frac{1}{100}\right)}\approx-.301  

4

none of these

7

Fill in the Blanks

Evaluate the logarithm. Round your answer to the nearest thousandth. (3 decimal places)

 log⁡7(35)\log_7\left(\frac{3}{5}\right)  



Type answer...

8

Fill in the Blanks

Evaluate the logarithm. Round your answer to the nearest thousandth. (3 decimal places)

 8log⁡(13)408\log_{\left(\frac{1}{3}\right)}40  



Type answer...

9

Use the change of base rule to simplify

 log⁡b8log⁡b2\frac{\log_b8}{\log_b2}  

  • Rewrite as division  log⁡b8÷log⁡b2\log_b8\div\log_b2  

  • Apply the change of base rule  log⁡8log⁡b÷log⁡2log⁡b\frac{\log8}{\log b}\div\frac{\log2}{\log b}  

  • Division means to multiply by the reciprocal  log⁡8log⁡b⋅log⁡blog⁡2\frac{\log8}{\log b}\cdot\frac{\log b}{\log2}  

  • Cancel the common factor  log⁡b\log b  

10

  •  log⁡8log⁡2\frac{\log8}{\log2}  

  • Use the change of base rule backwards  log⁡28\log_28  

  • Evaluate 3

11

Simplify

 log⁡a18⋅log⁡3a\log_a18\cdot\log_3a  

  • Change of base rule:  log⁡18log⁡a⋅log⁡alog⁡3\frac{\log18}{\log a}\cdot\frac{\log a}{\log3}  

  • Cancel common factor  log⁡a\log a  

  •  log⁡18log⁡3\frac{\log18}{\log3}  

  • Use the change of base rule backwards

  •  log⁡3(18)\log_3\left(18\right)  

12

Multiple Choice

Simplify

 log⁡3log⁡n3\frac{\log3}{\log_n3}  

1

1

2

log 3

3

 log⁡n1\log_n1  

4

log n

13

Multiple Choice

Simplify

 log⁡3a⋅log⁡3\log_3a\cdot\log3  

1

1

2

 log⁡3(3a)\log_3\left(3a\right)  

3

log 3a

4

log a

14

Homework in Khan Academy"

  • 1. Evaluate logarithms change of base rule

    2. Use the logarithm change of base rule

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Change of Base Rule

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