Math 1332 Section 10A

Math 1332 Section 10A

Fundamentals of Geometry

45. Find the perimeter and area.

Fill in the Blanks

Fill in the Blanks

 47.

A picture window has a length of 8 feet and a height of 6 feet, with a semicircular cap on each end. How much metal trim is needed for the perimeter of the entire window, and how much glass is needed for the opening of the window?

Fill in the Blanks

Fill in the Blanks

49.

Refer to Figure 10.14, showing the region to be covered with plywood under a set of stairs. Suppose that the stairs rise at a steeper angle and are 11 feet tall. What is the area of the region to be covered in that case?

49.

• Refer to Figure 10.14, showing the region to be covered with plywood under a set of stairs. Suppose that the stairs rise at a steeper angle and are 11 feet tall. What is the area of the region to be covered in that case?

• A = 1/2 (12) (11)

• = 66 square feet = $66\ ft^2$  

51.

 A parking lot is shaped like a parallelogram and bounded on four sides by streets, as shown in Figure 10.23. How much asphalt (in square yards) is needed to pave the parking lot?

Fill in the Blanks

59.

• Find the area of the whole figure.

• 12 meters * 250 meters * 60 meters

• = 180,000 cubic meters

• Find 30% of 180,000 cubic meters.

• (0.30)(180,000) = 54,000 cubic meters =

   $54,000\ m^3$  

Open Ended

Squirrels and humans are both mammals that stay warm through metabolism that takes place in the body volume. Mammals must constantly generate internal heat to replace the heat that they lose through the surface area of their skin.

75. In general terms, how does the surface-area-to-volume ratio of a squirrel compare to that of a human being?

Open Ended

Squirrels and humans are both mammals that stay warm through metabolism that takes place in the body volume. Mammals must constantly generate internal heat to replace the heat that they lose through the surface area of their skin.

76. Which animal must maintain a higher rate of metabolism to replace the heat lost through the skin: squirrels or humans? Based on your answer, which animal would you expect to eat more food in proportion to its body weight each day? Explain.

Fill in the Blanks

84.

• Full rectangle 20*10 = 200

• Garden = 16

• Half circle = (3.14)(5^2) (1/2) = (3.14)(25)(1/2) = 39.25

• Full rectangle - garden - patio = 200 - 16 - 39.25

• = 144.75 square meters

85.

• Human Lung. The human lung has approximately 300 million nearly spherical air sacs (alveoli), each with a diameter of about 1/3 millimeter. The key feature of the air sacs is their surface area, because on their surfaces gas is exchanged between the bloodstream and the air.

• a. What is the total surface area of the air sacs? What is the total volume of the air sacs?

•  $SA\ =\ 4\pi r^2$  
  

•  $SA\ =\ 4\ \left(\ 3.14\right)\left(\frac{1}{6}\right)^2\approx0.3489\ mm^2$  
  

• Multiply by 300 million   $\approx\ 1.05\ \times10^8=105,000,000\ mm^2$ 

85.

• Human Lung. The human lung has approximately 300 million nearly spherical air sacs (alveoli), each with a diameter of about 1/3 millimeter. The key feature of the air sacs is their surface area, because on their surfaces gas is exchanged between the bloodstream and the air.

• a. What is the total surface area of the air sacs? What is the total volume of the air sacs?

•  $V=\frac{4}{3}\pi r^3$  
  

•  $V=\frac{4}{3}\left(3.14\right)\left(\frac{1}{6}\right)^3\approx0.0193827$  

• Multiply by 300 million:  $\approx5.81\times10^6\ mm^3$  

85.

• The human lung has approximately 300 million nearly spherical air sacs (alveoli), each with a diameter of about 1/3 millimeter. The key feature of the air sacs is their surface area, because on their surfaces gas is exchanged between the bloodstream and the air.

• b. Suppose a single sphere were made that had the same volume as the total volume of the air sacs. What would be the radius and surface area of such a sphere? How would this surface area compare to that of the air sacs?

•  $V=\frac{4}{3}\pi r^3$  

•  $5.8\times10^6=\frac{4}{3}\pi r^3$ 
  

85. b.)

•  $5.8\times10^6\div\left(\frac{4}{3}\pi\right)\ =\ r^3$  
  

•  $r^3=1.3846\times10^6$  

•  $r=^3\sqrt{1.3846\times10^6}$  

•  $=111.46\ mm\ \approx\ 112\ mm$  is the radius of big sphere

85. b.)

•  $SA=4\pi r^2$  

•  $SA=4\left(3.14\right)\left(112\right)^2$  

•  $=157552.64\ \approx1.58\times10^5\ mm^2$  is the surface area of big sphere

85. b.)

•  $\frac{Surface\ Area\ of\ Big\ Sphere}{Surface\ Area\ of\ Little\ Sphere}=\frac{1.05\times10^8}{1.58\times10^5}$  

•  $\approx664.56\ \approx670\ times\ greater$  

85. c.)

• If a single sphere had the same surface area as the total surface area of the air sacs, what would be its radius? Based on your results, comment on the design of the human lung.

•  $SA=4\pi r^2$  

•  $1.05\times10^8=4\pi r^2$  

•  $r^2=\frac{\left(1.05\times10^8\right)}{4\pi}\approx8.36\times10^6$  

•  $r=\sqrt{8.36\times10^6}\approx2891.34\ mm$  

• 2.89 meters / for their relatively small volume, the air sacs have a very large surface area

87.

• The English Channel Tunnel, or “Chunnel,” runs a distance of 50.45 kilometers from Dover, England, to Calais, France. The Chunnel actually consists of three individual, adjacent tunnels, each shaped like a half-cylinder with a radius of 4 meters (the height of the tunnel). How much earth (volume) was removed to build the entire Chunnel?

•  $V=\pi r^2h$      (convert 50.45 km to 50450 m)

•  $V=\left(3.14\right)\left(4\right)^2\left(50450\right)\approx2,543,608$  

87.

• There are 3 tunnels. Multiply by 3 to get 7,603,824 cubic meters.

• Each tunnels is a half, so divide by 2. (Alternatively, one could multiply by 3/2)

• 3,801,912 = 3.8 x 10⁶ cubic meters