Independent Events

Independent Events

Additional Practice

A deck of Cards

• Total cards: 52

• Suits: 4

• Spades: 13

• Diamonds: 13

• Cloves: 13

• Hearts: 13

Compound Events

• Independent Events: one event does not affect the outcome of another event.

• P(A and B) = P(A) x P(B)

• Remember: "AND" means Multiply

• Ratio: Favorable / Total

Multiple Choice

Geraldo has a deck of cards and a bag of marbles with 4 red, 6 blue, 3 green, and 2 yellow marbles. What is the probability that he draws a 7 out of the deck of cards and then pulls a blue marble out of the bag? HINT: "AND" means to Multiply.

• P(Draws 7) = 4/52 = 1/13

  P(Blue) = 6/15

  P(7 & Blue) = 1/13 + 6/15 = 3 ⁄ 15

• P(Draws 7) = 4/52 = 1/13

  P(Blue) = 6/15

  P(7 & Blue) = 1/13 x 6/15 = 2 ⁄ 65

Answer

Geraldo has a deck of cards and a bag of marbles with 4 red, 6 blue, 3 green, and 2 yellow marbles. What is the probability that he draws a 7 out of the deck of cards and then pulls a blue marble out of the bag? HINT: "AND" means to Multiply.

P(Draws 7) = 4/52 = 1/13

P(Blue) = 6/15 = 2/5

P(7 & Blue) = 1/13 x 2/5 = 2 ⁄ 65

Multiple Choice

Lucy has the spinner pictured and spins it twice in a row. What is the probability that she lands on blue first and then on yellow or green?

• P1(Blue)= 1/4

  P2(Yellow Or Green)= 1/4 + 1/4 = 1/2

  P(Blue & Yellow or Green) = 1/4 + 1/2 = 6/8

• P1(Blue)= 1/4

  P2(Yellow Or Green)= 1/4

  P(Blue & Yellow or Green) = 1/4 x 1/4 = 1/16

• P1(Blue)= 1/4

  P2(Yellow Or Green)= 1/4 + 1/4 = 1/2

  P(Blue & Yellow or Green) = 1/4 x 1/2 = 1 ⁄ 8

Answer:

Lucy has the spinner pictured and spins it twice in a row. What is the probability that she lands on blue first and then on yellow or green?

P1(Blue)= 1/4

P2(Yellow Or Green)= 1/4 + 1/4 = 1/2

P(Blue & Yellow or Green) = 1/4 x 1/2 = 1 ⁄ 8

Multiple Choice

What is the probability of rolling a dice and landing on a 4, and then rolling the dice again and landing on any even number?

• P(4)= 1/6

  P(Even)= 1/2

  P(4 & Even)= 1/6 + 1/2 = 2/3

• P(4)= 1/6

  P(Even)= 2/3

  P(4 & Even)= 1/6 x 2/3 = 5/6

• P(4)= 1/6

  P(Even)= 2/6

  P(4 & Even)= 1/6 + 2/6 =1 ⁄ 2

• P(4)= 1/6

  P(Even)= 1/2

  P(4 & Even)= 1/6 = 1/2 = 1 ⁄ 12

Answer

What is the probability of rolling a dice and landing on a 4, and then rolling the dice again and landing on any even number?

P(4)= 1/6

P(Even)= 1/2

P(4 & Even)= 1/6 = 1/2 = 1 ⁄ 12

Multiple Choice

Ricardo has the spinner pictured here and a bag of marbles filled with 2 red marbles, 3 green marbles, and 3 blue marbles. What is the probability that Ricardo spins red on the spinnerandpicks a red marble out of the bag?

• P(Red)= 1/4

  P(Red Marble)= 2/8 = 1/4

  P(Red & Red)= 1/4 x 1/4

  = 1 ⁄ 16

• P(Red)= 1/4

  P(Red Marble)= 2/8 = 1/4

  P(Red & Red)= 1/4 + 1/4

  = 1 ⁄ 2

• P(Red)= 1/4

  P(Red Marble)= 2/2 = 1

  P(Red & Red)= 1/4 x 1

  = 1 ⁄ 4

• P(Red)= 1/4

  P(Red Marble)= 1/2

  P(Red & Red)= 1/4 x 1/2

  =1 ⁄ 8

Answer

Ricardo has the spinner pictured here and a bag of marbles filled with 2 red marbles, 3 green marbles, and 3 blue marbles. What is the probability that Ricardo spins red on the spinnerandpicks a red marble out of the bag?

P(Red)= 1/4

P(Red Marble)= 2/8 = 1/4

P(Red & Red)= 1/4 x 1/4

= 1 ⁄ 16

Multiple Choice

What is the probability of rolling a 2 on a diceANDpulling a spade out of a deck of cards?

• P(2)= 1/6

  P(Spade)= 13/52 = 1/4

  P(2 & Spade) = 1/6 + 1/4 = 1 ⁄ 10

• P(2)= 1/6

  P(Spade)= 13/52 = 1/4

  P(2 & Spade) = 1/6 + 1/4 = 1 ⁄ 12

• P(2)= 1/6

  P(Spade)= 13/52 = 1/4

  P(2 & Spade) = 1/6 x 1/4 = 1 ⁄ 24

• P(2)= 1/6

  P(Spade)= 1

  P(2 & Spade) = 1/6 x 1 = 1 ⁄ 6

Answer

What is the probability of rolling a 2 on a dice AND pulling a spade out of a deck of cards?

P(2)= 1/6

P(Spade)= 13/52 = 1/4

P(2 & Spade) = 1/6 x 1/4 = 1 ⁄ 24

Poll

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