

5.1-5.5 Review (AA2)
Presentation
•
Mathematics
•
9th - 12th Grade
•
Hard
+2
Standards-aligned
Edward Jones
Used 4+ times
FREE Resource
8 Slides • 13 Questions
1
5.1-5.5 Review (AA2)

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Sections / Topics in 5.1-5.5
5.1 Operations with Polynomials
5.2 Polynomial Division (Synthetic and Long)
5.3 Polynomials as Functions
5.4 Graphs of Polynomial Functions
5.5 Factoring and Solving Polynomial Equations
3
5.1 Questions
The following are exercises within 5.1. Be prepared to see these kinds in the assessment!
4
Multiple Choice
Simplify
(4r2+3r−1)−(3r2−5r+4) .7r2+3r−5
r2+8r−5
r2−2r+5
5
Multiple Choice
Simplify
(3x3)2 (−x3)9x6
−3x8
−9x9
6
Multiple Choice
Simplify
2x3y514x4y7xy
y47x
y7x
7
5.2 Questions
Be prepared to see these kinds on the assessment!
8
Multiple Choice
Divide
y+26y3+13y2−10y−24 with either synthetic or long division.6y2+y−12
6y2−y+12 −y+24
y2−6y+2
9
Multiple Select
If you were to synthetically divide
a+2a4+5a3+2a2−6a+4 which of the following are true?2 would go in the little box
-2 would go in the little box
You add the columns
You subtract the columns
You bring the first coefficient straight down
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5.3 Questions
Be ready to see these topics in the assessment!
11
Multiple Choice
Select the degree and leading coefficient of
f(x)=3x3−7x2+x−9Degree: 3
Leading Coefficient: 3
Degree: 2
Leading Coefficient: 3
Degree: 2
Leading Coefficient: -7
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Multiple Choice
Find f(-2), if
f(x)=2x2−x+713
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17
7
13
5.4 Questions
These may be on the assessment!
14
Multiple Select
Select the following that are TRUE.
The function has 2 relative maxima.
The function has 2 relative minima.
The function has 3 relative maxima.
The function has 3 relative minima.
The function is odd.
15
Multiple Choice
How many real solutions does the graph have?
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3
5
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5.5 Questions
These types could be on the assessment...
17
Multiple Choice
What would be the method to factor the following polynomial?
GCF
Quadratic Trinomial
Grouping
18
Multiple Choice
Choose the proper factorization for the following sum of cubes.
(p+3)(p2−3p+9)
(p+3)(p−3)
(p−3)(p2+3p+9)
19
Multiple Choice
I'm solving an equation and I get to something like this:
(x−2)(x2+3x+8)=0The second factor can't be factored or broken down any more, so what should I do to solve for x?
It can't be factored or solved.
Use the quadratic formula for the second factor since it's second degree.
Check for errors because quadratic trinomials always factor.
20
Multiple Choice
Finish the following and solve the polynomial equation.
x3−x2−9x+9=0
(x2−9)(x−1)=0x2−9=0 or x−1=0
x=±3, −1
x=±3, 1
x=9, 1
x= −9, −1
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That's all!
Be sure to review old notes and homework if you weren't confident with these topics.
5.1-5.5 Review (AA2)

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