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Geometry Section 9.1 Tangent  Day 2

Geometry Section 9.1 Tangent Day 2

Assessment

Presentation

Mathematics

9th - 12th Grade

Medium

Created by

Shane Devlin

Used 10+ times

FREE Resource

11 Slides • 14 Questions

1

Geometry Section 9.1 Tangent

Day 2
Finding and using the Tangent ratio.


How do we use the tangent ratio to find missing lengths and missing angles in triangles?

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2

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3

Multiple Choice

Question image

Find ACAB\frac{AC}{AB} = ?

1

43\frac{4}{3}  

2

34\frac{3}{4}  

3

35\frac{3}{5}

4

45\frac{4}{5}

4

Multiple Choice

Question image

Find BCAB\frac{BC}{AB} = ?

1

43\frac{4}{3}  

2

34\frac{3}{4}  

3

35\frac{3}{5}

4

45\frac{4}{5}

5

Multiple Choice

Question image

Find BCAC\frac{BC}{AC} = ?

1

43\frac{4}{3}  

2

34\frac{3}{4}  

3

35\frac{3}{5}

4

45\frac{4}{5}

6

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Talk it over with a neighbor

Find AB and BC

7

Fill in the Blanks

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Type answer...

8

Multiple Choice

Question image

Find BCBC = ?

1

3\sqrt{3}  

2

33\frac{\sqrt{3}}{3}  

3

636\sqrt{3}

4

12312\sqrt{3}

5

232\sqrt{3}

9

Multiple Choice

Question image

Find ACAB\frac{AC}{AB} = ?

1

3\sqrt{3}  

2

33\frac{\sqrt{3}}{3}  

3

12\frac{1}{2}

4

21\frac{2}{1}

10

Multiple Choice

Question image

Find BCAC\frac{BC}{AC} = ?

1

3\sqrt{3}  

2

33\frac{\sqrt{3}}{3}  

3

12\frac{1}{2}

4

21\frac{2}{1}

11

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12

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13

Multiple Choice

Question image

What is Tan B = ?

1

513\frac{5}{13}

2

512\frac{5}{12}

3

125\frac{12}{5}

4

1213\frac{12}{13}

14

Multiple Choice

Question image

What is Tan A = ?

1

513\frac{5}{13}

2

512\frac{5}{12}

3

125\frac{12}{5}

4

1213\frac{12}{13}

15

Fill in the Blanks

Type answer...

16

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17

Using the tangent ratio to find a missing side.

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18

Using the tangent ratio to find a missing angle.

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19

Multiple Choice

Question image

Find the value of x to the nearest degree.

1

29

2

61

3

30

4

28

20

Multiple Choice

Question image

Find the value of x to the nearest unit.

1

282

2

2381

3

54

4

124

21

What to do when x is on the bottom

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22

Multiple Choice

Solve:    Tan 19° =48xSolve:\ \ \ \ Tan\ 19\degree\ =\frac{48}{x}

1

x = 16.5

2

x = 17.1

3

x = 139.4

4

x = 0.55

5

x = 4175.4

23

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24

Multiple Choice

Question image

Solve:  Tan x° = 32100Solve:\ \ Tan\ x\degree\ =\ \frac{32}{100}

1

17.7°17.7\degree

2

0.056°0.056\degree

3

72.3°72.3\degree

4

18.7°18.7\degree

25

Homework Section 9.1 Day 2

  • Formative 9.1

  • # 1 - 15 All

Geometry Section 9.1 Tangent

Day 2
Finding and using the Tangent ratio.


How do we use the tangent ratio to find missing lengths and missing angles in triangles?

media

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