Work Review

Work Review

Fill in the Blanks

Energy transfer of an object due to force. represented in terms of force and displacement

Multiple Choice

Work is measured in terms of

• Joules

• kg

• N

• m/s

Work

The energy transfer of an object in terms of force and displacement

Measured in Joules

Work Angles

• Force and Displacement are along the same axis in the same direction W=Fd

• Force and Displacement are opposite W=Fd(cos 180^o)

• If Force and Displacement are perpindicular to one another then W=0

Multiple Choice

Who is doing Work

• man

• boxes

Multiple Choice

The Work of the box is

• +

• -

• 0

Inclined Plane

• F _parallel = sliding force due to gravity

• F_f = force of friction (opp of direction)

• F_a= applied Force

• W_net= W_Fp +/- W_Ff +/- W_Fa

Multiple Choice

A 50 Kg box is sliding down a hill with a 2.4 N frictional force at an incline of 37^o. The box travels 9m before coming to a rest. What is the net Work done on the box?

• 2655 J

• 21.6 J

• 2633 J

• 26.3 J

Kinetic Energy

• Energy in motion

• KE=1/2mv²

Work

• The change in KE

•  $\Delta KE=\frac{1}{2}m_fv_f^2\ -\ \frac{1}{2}m_iv_i^2$  

Fill in the Blanks

A 28 kg box sits at rest on the top of an incline at 17^o for a distance of .7 m. The box slides with a constant velocity of 2 m/s . what is the net Work done by the box? ones place

Fill in the Blanks

A 28 kg box sits at rest on the top of an incline at 17^o for a distance of .7 m. The box slides with a constant velocity of 2 m/s . what is the net Force?

Fill in the Blanks

A 28 kg box sits at rest on the top of an incline at 17^o for a distance of .7 m. The box slides with a constant velocity of 2 m/s . What is the coefficient due to friction if F _parallele= 50.76