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357: Choose a Factoring Method Lesson

357: Choose a Factoring Method Lesson

Assessment

Presentation

Mathematics

9th Grade

Medium

Created by

Molly McKee

Used 5+ times

FREE Resource

7 Slides • 12 Questions

1

Choose a Factoring Method

I can identify the appropriate factoring method given a polynomial.

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2

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3

Multiple Choice

First step of Factoring is

1

Finding the GCF

2

Divide by the GCF

3

Multiply by the GCF

4

Subtract by the GCF

4

Multiple Choice

Factor (GCF):
12x + 9
1
3 (4x + 3)
2
x (12+9)
3
3 (4x - 3)
4
Prime

5

Multiple Choice

The G.C.F of the expression 30a3b2 + 20a2b + 35a4b2 is:

1

30a4b2

2

20a4b2

3

5a2b

4

5a4b2

6

Difference of Squares

Are there two terms (binomial)?

Does it have degree = 2?

Is it a difference?

Are both terms Perfect Squares?

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7

Multiple Choice

x2 - 25

1

( x + 5 ) ( x - 5 )

2

( x - 5 ) ( x - 5 )

3

( x + 5 ) ( x + 5 )

4

Unfactorable

8

Multiple Choice

x2 - 225

1

( x + 15) ( x + 15)

2

Unfactorable

3

( x - 15) ( x + 15)

4

( x - 15) ( x - 15)

9

Multiple Choice

4x2 - 64y2

1

Unfactorable

2

( 2x - 32y) (2 x + 32y)

3

( 2x - 8y) (2 x - 8y)

4

( 2x - 8y) (2 x + 8y)

10

Trinomials (a=1 & a>1)

Identify a, b, and c

Multiply a and c

Find the factors of ac that sum to b

(use the X strategy for organizing)


Now you have 4 terms and you can factor by grouping using the box method.

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11

Multiple Choice

Factor
n2 + 16n + 63
1
(n-7)(n+4)
2
(n+7)(n-9)
3
(n-3)(n-10)
4
(n+7)(n+9)

12

Multiple Choice

Factor
x2 + 4x + 3
1
(x - 1)(x - 3)
2
(x + 1)(x + 3)
3
(x - 1)(x + 3)
4
(x + 1)(x - 3)

13

Multiple Choice

Factor

4x2-25x+25

1

4(x-5)(x+5)

2

(x+5)(4x+5)

3

(x-5)(4x-5)

4

(x+2)(9x+1)

14

Multiple Choice

Factor
3a2 + 4a + 1
1
(7a-10)(a-8)
2
Not factorable
3
(3a+1)(a+1)
4
(3a-1)(a-1)

15

Factor by Grouping (Box Method)

Draw a box

Put each term in a box in order

Find the GCF of each column and each row

If there is no GCF, then write 1

If there is a negative in the first box, then the GCF should be negative

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16

Multiple Choice

Factor by grouping:
5n³-10n²+3n-6
1
(5n²+3)(n-2)
2
(5n²-3)(n-2)
3
(5n³+3)(n-2)
4
10n(n²-6)

17

Multiple Choice

Factor by grouping:

4p³+8p²+3p+6

1

(2p²+3)(p+2)

2

(2p²+6)(p+4)

3

(4p²+3)(p+2)

4

(4p²+8p)(3p+6)

18

Summary

  • Factor out GCF (if needed)

  • Decide which method by the number of terms

  • 2 terms - Check for DIFFERENCE OF SQUARES

  • 3 terms - Use the ac method for finding factors, then the box method

  • 4 terms - Use the box method

  • Write your answer as a series of binomial products

  • Put the GCF from Step 1 (if you had one) out front

19

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Choose a Factoring Method

I can identify the appropriate factoring method given a polynomial.

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