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Power Series

Power Series

Assessment

Presentation

Mathematics

University

Medium

Created by

Andrew Forisha

Used 12+ times

FREE Resource

4 Slides • 3 Questions

1

Power Series

The series we've been working up to this whole time.

Slide image

2

Multiple Choice

 n=1a(r)(n1)\sum_{n=1}^{\infty}a\left(r\right)^{\left(n-1\right)}  What is this series known as?

1

Geometric Series

2

Alternating Series

3

 Telescoping Sum 

4

P-Series

3

Multiple Choice

If I do a partial fraction decomposition on a series that means it's a telescoping series.

1

True

2

False

4

Multiple Choice

 n=1(1n)p\sum_{n=1}^{\infty}\left(\frac{1}{n}\right)^p  What is this series known as?

1

Alternating Series

2

Geometric Series

3

Telescoping Sum

4

P-Series

5

Power Series

  •  n=0cn(xa)n=c0+c1(xa)+c2(xa)2+...\sum_{n=0}^{\infty}c_n\left(x-a\right)^n=c_0+c_1\left(x-a\right)+c_2\left(x-a\right)^2+... 

  • There are only 3 possibilities for convergence:

  • Converges only when x=a

  • Converges for all x

  • There is a positive number R such that the series converges if |x-a|<R and diverges for |x-a|>R

6

Radius of Convergence

  • When x=a, R=0

  • When the power series converges for all x, R= \infty  

  • Bessel Functions are a great example of a Power Series....Some of them can explain the temperature distribution on a plate or the vibration a circular drum head.

  • We're going to walk through how to find the radius of convergence by using the ratio test.

7

Ratio Test

  •  n=0an\sum_{n=0}^{\infty}a_n  is absolutely convergent when  limna(n+1)an=L<1\lim_{n\rightarrow\infty}\left|a_{\frac{\left(n+1\right)}{a_n}}\right|=L<1  

  • Find the radius of convergence of  n=0(1)nx2n22n(n!)2\sum_{n=0}^{\infty}\frac{\left(-1\right)^nx^{2n}}{2^{2n}\left(n!\right)^2}  using the ratio test.

  •  a(n+1)an=(1)(n+1)x2(n+1)22(n+1)[(n+1)!]222n(n!)2(1)nx2n\left|\frac{a_{\left(n+1\right)}}{a_n}\right|=\left|\frac{\left(-1\right)^{\left(n+1\right)}x^{2\left(n+1\right)}}{2^{2\left(n+1\right)}\left[\left(n+1\right)!\right]^2}\cdot\frac{2^{2n}\left(n!\right)^2}{\left(-1\right)^nx^{2n}}\right|  

  • At this point, it's an algebraic simplification.

  • As n \rightarrow  \infty , the limit approaches 0<1 for all x, so the Radius of convergence is ( , -\infty,\ \infty 

Power Series

The series we've been working up to this whole time.

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