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Dimensional Analysis

Dimensional Analysis

Assessment

Presentation

•

Mathematics

•

6th - 12th Grade

•

Practice Problem

•

Hard

Created by

Katherine Furgeson

Used 46+ times

FREE Resource

23 Slides • 0 Questions

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Dimensional Analysis

Veterinary Science

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Dimensional Analysis can also be called the Unit Factor Method or the Label Method.

It's a way of converting through different types of measurement to end up with what is needed.

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Consider the following problem: A cat weighing 11 lbs requires an antibiotic at a dose of 15 mg/kg. The antibiotic comes in a concentration of 125 mg/5mL. How many mL do you give?

Here we have to go from lbs to kg then we need to figure mg/kg then mg/mL. This requires multiple conversions. Here's where Dimensional Analysis comes in handy!

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Let's start with a YouTube clip.....

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Let's do a fun one!!! Here we need the conversion factor for:

1. Students per class

2. Slices per student

3. Slices in each pizza

4. Price per pizza


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Here are the conversion factors!

Notice that every segment is equal. 25 Students = 1 class. 2 slices = 1 student. 1 pizza = 5 slices. $10.00 = 1 pizza.

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Cross out the units that match but leave the numerical values.

  • Students

  • Slices

  • Pizza

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Multiply and divide the numerical values left.

  • Multiply 25 x 2 x 1 x 10 = 500

  • Multiply 1 x 1 x 5 x 1 = 5

  • Then divide  500÷5 =500\div5\ =  100

  •  100 dollars1 class\frac{100\ dollars}{1\ class}  

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Our final answer is $100 to feed the entire class.

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Let's look back at our initial problem again:

A cat weighing 11 lbs requires an antibiotic at a dose of 15 mg/kg. The antibiotic comes in a concentration of 125 mg/5mL. How many mL do you give?

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Set up the problem with the conversion factors:

11 lbs = 1 cat. 1 kg = 2.2 lbs. 15 mg = 1 kg. 5 mL = 125 mg.

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Cross off the units that cancel out.

  • lbs

  • kg

  • mg

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Multiply across then divide

  •  11×1×15×5=82511\times1\times15\times5=825  

  •  1×2.2×1×125=2751\times2.2\times1\times125=275  

  •  825275=3\frac{825}{275}=3  

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Our answer is 3 mL

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Let's try one more!

A cat weighing 4.5 kg needs insulin at 1.5 international units (IU) per kg. The insulin comes in a strength of 10 IU per mL. How much insulin do you give? (answer to nearest tenth of a mL)

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Find the conversion factors and set up the problem.

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Here is our problem!

4.5 kg = 1 cat. 1.5 IU = 1 kg. 1 mL = 10 IU.

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Cross off the units that cancel each other out. Leave the numerical value.


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Multiply across then end with division.

  •  4.5×1.5×1=6.754.5\times1.5\times1=6.75  

  •  1×1×10=101\times1\times10=10  

  •  6.7510=0.675\frac{6.75}{10}=0.675  

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0.675 rounded to the nearest tenth is 0.7

Our answer is 0.7 mL

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YOU CAN DO IT!!!!!

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Dimensional Analysis

Veterinary Science

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