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Percent yield and Limiting Reactant

Percent yield and Limiting Reactant

Assessment

Presentation

Chemistry

9th - 12th Grade

Practice Problem

Easy

NGSS
HS-PS1-7

Standards-aligned

Created by

James Medalla

Used 24+ times

FREE Resource

6 Slides • 6 Questions

1

Percent yield and Limiting Reactant

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2

Open Ended

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In your own words, define limiting reactant and explain why it is important.

3

Types of reactants

Limiting Reactant (Reagent)

Limits the reaction by determining how much product can be produced.


Excess Reactant (Reagent)

Not used up completely in a reaction (leftovers)

4

Open Ended

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Think about this scenario:

You find your grandma's recipe for your favorite kind of cookies you loved eating as a kid.

The measurements for the liquids in the recipe are all written in liters/milliliters.

You only have measuring cups that measure in teaspoon/tablesppon/cups.


What do you do to measure the correct amount of liquid?

5

2 Na + S -->Na2S

GC=Grilled Cheese
Equation reads

 7 GC( 2 Bread1 GC\frac{2\ Bread}{1\ GC} ) =14 bread

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6

Open Ended

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What about the cheese? How many slices of cheese are needed to make 7 grilled cheese sandwiches?


Answer with the format

....GC ( .....Cheese slices.....GC\frac{.....Cheese\ slices}{.....GC}  ) = .....Cheese slices

7

Types 1 and 2 always start with moles

Type 1: (Mole-Mole)
B= unknown value (what we are solving for)
A=Given value (found in the problem)
 molB=mol knownA  molBmolAmol_B=mol\ known_A\ \cdot\ \frac{mol_B}{mol_A}  



Type 2: (Mole-Mass)

 gramsB=mol knownA  molBmolAMolar MassB1 molBgrams_B=mol\ known_A\ \cdot\ \frac{mol_B}{mol_A}\cdot\frac{Molar\ Mass_B}{1\ mol_B}  

8

Types 3 and 4 always start with mass

Type 3: (Mass-Mole)

 molB=grams knownA  1 molAMolar MassA molBmolAmol_B=grams\ known_A\ \cdot\ \frac{1\ mol_A}{Molar\ Mass_A}\cdot\ \frac{mol_B}{mol_A}  


Type 4: (Mass-Mass)
 gramsB=grams knownA 1 mol AMolar MassA molBmolAMolar MassB1 molBgrams_B=grams\ known_A\ \cdot\frac{1\ mol\ _A}{Molar\ Mass_A}\ \cdot\frac{mol_B}{mol_A}\cdot\frac{Molar\ Mass_B}{1\ mol_B}  

9

Percent Yield

 % yield = actual yieldtheoretical yield  100\%\ yield\ =\ \frac{actual\ yield}{theoretical\ yield}\ \cdot\ 100  

Actual yield is given (determined through experimentation)

Theoretical yield is determined by stoichiometry (If the reaction fully completed)

10

Multiple Choice

Using this problem:

Phosphorous reacts with bromine to form phosphorous tribromide. 35.0 grams of bromine are reacted and 27.9 grams of phosphorous tribromide are formed.


2 P + 3 Br2 --> 2 PBr3


Answer the following question:

Which of these is the actual yield of phosphorous tribromide?

1

35 grams

2

27.9 grams

3

39.5 grams

4

23.9 grams

11

Multiple Choice

Using this problem:

Phosphorous reacts with bromine to form phosphorous tribromide. 35.0 grams of bromine are reacted and 27.9 grams of phosphorous tribromide are formed.


2 P + 3 Br2 --> 2 PBr3

Answer the following question:

To solve for the theoretical yield, which type of stoichiometry must be performed?

1

Type 1 (Mole-Mole)

2

Type 2 (Mole-Mass)

3

Type 3 (Mass-Mole)

4

Type 4 (Mass-Mass)

12

Multiple Choice

When elements A and B react completely, they would form 100 grams of AB (ideally). However, transfer loss occured and only 80 grams formed from experimentation


What is the percent yield for this reaction?

1

20%

2

33%

3

100%

4

80%

Percent yield and Limiting Reactant

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