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Vertex Form of Parabolas

Vertex Form of Parabolas

Assessment

Presentation

Mathematics

9th - 11th Grade

Medium

CCSS
HSF-IF.C.7A, HSA.APR.C.4, 8.EE.A.2

+3

Standards-aligned

Created by

John Phillips

Used 5+ times

FREE Resource

14 Slides • 27 Questions

1

Vertex Form of Parabolas

 y=a(xh)2+ky=a\left(x-h\right)^2+k  

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2

3 Forms of Quadratic Functions

  • Standard

  • Factored

  • Vertex

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3

Fill in the Blank

 f(x)=3x2+84xf\left(x\right)=3x^2+8-4x  



Find the y-intercept of the function, type ONLY the y-value:

4

Fill in the Blank

 f(x)=x271f\left(x\right)=x^2-71  



Find the y-intercept of the function, type ONLY the y-value:

5

To find the x-intercepts (aka roots aka zeros)

  • We can factor!

  • We can use the quadratic formula!

  • We can even use complete the square (but probably won't because it's going to be used elsewhere!)

6

Multiple Choice

Which is another way of correctly expressing

(x - 3)(x - 3)?

1

(x2 - 32)

2

(x2 - 3)

3

(x + 3)(x - 3)

4

(x - 3)2

7

On the next slide

The next slide contains a factoring methods review video. Watch it only if you don't remember how to factor. Then proceed to the next slide (#9).

8


9

Multiple Choice

x2 − 7x − 18

1

(x − 9)(x + 2)

2

(x + 9)(x + 2)

3

(x − 9)(x - 2)

4

(x − 9)(x - 2)

10

Multiple Choice

Factor the expression: w2 - 15w - 54

1

(w + 6)(w - 9)

2

(w + 3)(w - 18)

3

(w + 2)(w - 27)

4

(w - 6)(w + 9)

11

Multiple Choice

Factor the expression: 10v2 + 11v - 8

1

(5v + 8)(2v + 1)

2

(v + 8)(v - 1)

3

(5v + 8)(2v - 1)

4

(10v - 8)(v + 1)

12

Making Connections

  • Ok, you know how to factor.

  • Now let's factor with purpose. First, we'll factor to SOLVE equations.

  • THEN, we'll factor to find the ROOTS of quadratic functions.

  • I hope you'll see it's essentially the same process.

13

14

15

Multiple Choice

Solve.

n2 - 5 = -4

1

n = ±√9

2

n = ±3

3

n = ±1

4

No real solution

16

Multiple Choice

Question image

What are the x-intercept/s of the function?

1

(3,0)

2

(-3,0)

3

(9,0) & (-9,0)

4

(-3, 0) & (3, 0)

17

Multiple Choice

What are the solutions to this equation? (x-3)(x+2)=0

1

x=3,-2

2

x=-3,2

3

x=2,3

4

x=3,2

18

Multiple Choice

True or false:

The solution, root, x-intercept, and zero of a problem are all the same thing.

1

True

2

False, because the solution and root are the same but the x-intercept and zero are different

3

False, because the x-intercept and root are the same but the zero and solution are different

4

False, they are all different

19

Multiple Choice

What are the zeros of the quadratic function?

y = x2 - 2x - 15

1

x = -2

x = -15

2

x = -3

x = 5

3

x = 3

x = -5

4

x = 1

x = -16

20

Multiple Choice

What are the x-interepts for the graph of the function: y = x2 - 3x - 10

1

-5, 2

2

-5, -2

3

5, -2

4

5, 2

21

Vertex Form

  • (h, k) is the point we call the vertex

  • It is the maximum or minimum point for the parabola

  • You read it DIRECTLY from the equation

  • Aside: Does this parabola have x-intercepts?

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22

x-intercepts?

  • No, this parabola does NOT touch the x-axis.

  • Therefore, we could say that it does not have any REAL roots

  • However, upon solving it, we would determine that it has IMAGINARY solutions...or roots...or zeros

  • More on this next week!

  • For now, watch the video on the next slide!

Slide image

23

24

Converting to Vertex Form

  • Complete the Square

  • Remember this!

  •  (b2)2\left(\frac{b}{2}\right)^2  

25

Multiple Choice

Which of the following equations matches standard form of a quadratic?

1

ax + by = c

2

y = a(x - h)2 + k

3

y = ax2 + bx + c

4

y = mx + b

26

Multiple Choice

In vertex form,


f(x) = a(x - h)2 + k


what does the h stand for?

1

the y-coordinate of the vertex

2

the x-coordinate of the vertex

3

the x-intercept

4

the y-intercept

27

Multiple Choice

The parabola y = 3(x + 1)2 + 3 has a vertex of

1

(3, 3)

2

(1, 3)

3

( - 1, 3)

4

(3, -1)

28

Multiple Choice

The parabola y = x2 - 2x + 4 will have a vertex of

1

(-1, 2)

2

(1, 2)

3

(-1, 3)

4

(1, 3)

29

Multiple Choice

Convert to vertex form:


y = x2 - 2x + 5

1

y = (x - 1)2 + 4

2

y = (x - 1)2 - 4

3

y = (x - 1)2 + 3

4

y = (x - 1)2 + 7

30

Multiple Choice

Convert to vertex form:


y = x2 + 8x + 2

1

y = (x + 4)2 - 14

2

y = (x + 4)2 - 6

3

y = (x + 4)2 - 18

4

y = (x + 4)2 + 6

31

Multiple Choice

Convert to vertex form:


y = x2 + 4x + 10

1

y = (x + 4)2 + 6

2

y = (x + 2)2 + 6

3

y = (x + 4)2 - 6

4

y = (x + 2)2 - 6

32

33

Multiple Choice

If a parabola has a vertex at (5, 0) and opens upward, how many x-intercepts will it have?

1

0

2

1

3

2

4

no way to tell

34

Multiple Choice

If a parabola has a vertex at (-3, 7) and opens downward, how many x-intercepts will it have?

1

0

2

1

3

2

4

no way to tell

35

36

Multiple Choice

Question image

Which equation matches the graph?

1

f(x)=(x1)2+4f\left(x\right)=\left(x-1\right)^2+4

2

f(x)=(x+4)21f\left(x\right)=\left(x+4\right)^2-1

3

f(x)=(x1)2+4f\left(x\right)=-\left(x-1\right)^2+4

4

f(x)=(x+4)21f\left(x\right)=-\left(x+4\right)^2-1

37

Multiple Choice

Question image

Which equations matches the graph above?

1

h(x)= (x+1)24h\left(x\right)=\ \left(x+1\right)^2-4

2

h(x)=(x+1)24h\left(x\right)=-\left(x+1\right)^2-4

3

h(x)=(x+4)21h\left(x\right)=\left(x+4\right)^2-1

4

h(x)=(x+4)2+1h\left(x\right)=-\left(x+4\right)^2+1

38

Multiple Choice

Question image

Which of the following is the correct equation for the given graph?

1

f(x) = (x - 2)2 - 1

2

f(x) = (x + 2)2 - 1

3

f(x) = -(x + 2)2 - 1

4

f(x) = -(x - 2)2 - 1

39

Multiple Choice

Question image

Which quadratic function is represented by the graph?

1

y = 2(x - 4)2 + 5

2

y = 2(x + 4)2 + 5

3

y = -2(x - 4)2 + 5

4

y = -2(x + 4)2 + 5

40

Multiple Choice

Question image

What is the equation of this graph?

1

f(x) = (x -5)2 + 1

2

f(x) = (x - 1)2 - 5

3

f(x) = (x + 1)2 - 5

4

f(x) = (x + 5)2 +1

41

Multiple Choice

Question image

What is the equation of this graph?

1

f(x) = (x -5)2 + 1

2

f(x) = (x - 1)2 - 5

3

f(x) = (x + 1)2 - 5

4

f(x) = (x + 5)2 +1

Vertex Form of Parabolas

 y=a(xh)2+ky=a\left(x-h\right)^2+k  

Slide image

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