

HPC Section 5.1 Part 1
Presentation
•
Mathematics
•
9th - 12th Grade
•
Medium
+2
Standards-aligned
Shane Devlin
Used 14+ times
FREE Resource
19 Slides • 28 Questions
1
PreCalculus
Section 5.1 Part 1
Using Fundamental Identities

2
Multiple Select
Given the diagram, which of the following statements are true?
x2+y2=r2
sinθ=ry
r=x+y
sin2θ+cos2θ=1
x=r2−y2
3
4
Identity Categories:
Reciprocal
Quotient
Pythagorean
Sum & Difference
Double Angle
Half Angle
For this part of our unit, we will be discussing Reciprocal, Quotient and Pythagorean Identities **MEMORIZE THEM!
5
6
Multiple Choice
Which of the following would be the definition of
cosθ ?
yx
rx
ry
xr
yr
7
Multiple Choice
Which of the following would be the definition of
cotθ ?
yx
rx
ry
xr
yr
8
Multiple Choice
Which of the following would be the definition of
secθ ?
yx
rx
ry
xr
yr
9
Multiple Choice
Which of the following would be the definition of
cscθ ?
yx
rx
ry
xr
yr
10
Reciprocal Identities:
11
Quotient Identities:
12
Multiple Choice
13
Multiple Choice
14
Multiple Choice
15
Multiple Choice
16
Multiple Choice
17
Multiple Choice
Use
cscx=2
find the other trig functions. sin x = ?
21
23
323
3
33
18
Multiple Choice
Use
cscx=2
find the other trig functions. If x is in the first quadrant what is cos x = ?
21
23
323
3
33
19
Multiple Choice
Use
cscx=2
find the other trig functions. If x is in the first quadrant what is sec x = ?
21
23
323
3
33
20
Multiple Choice
Use
cscx=2
find the other trig functions. If x is in the first quadrant what is tan x = ?
21
23
323
3
33
21
Pythagorean identity #1:
22
Pythagorean Identity #2
23
Pythagorean Identity #3
24
Multiple Choice
Rearrange:
sin2x+cos2x=1 to solve for: sin2x
sin2x=1−cos2x
sin2x=1+cos2x
sin2x=cos2x−1
25
Multiple Choice
Rearrange:
sin2x+cos2x=1 to solve for cos2x
cos2x=1−sin2x
cos2x=1+sin2x
cos2x=sin2x−1
26
Multiple Choice
Rearrange to solve for tan2θ :
1 + tan2θ= sec2θ
tan2θ = sec2θ + 1
tan2θ = sec2θ - 1
tanθ = secθ - 1
tan2θ = opp/adj
27
Multiple Choice
Rearrange so it equals 1:
1 + tan2x= sec2x
tan2x−sec2x=1
sec2x−tan2x=1
sec2x+tan2x=1
tan2x−1=sec2x
28
Multiple Choice
Solve the following for cot2θ :
1+cot2θ=csc2θ
1 = cot2θ + csc2θ
cot2θ =1 - csc2θ
cot2θ = csc2θ -1
cot2θ = adj/opp
29
IN CASE YOU DIDN'T GET THEM....HERE ARE ALL THE PYTHAGOREAN ARRANGEMENTS!
30
Multiple Select
sin2θ+cos2θ=1
Choose the equivalent equations?
sin2θ=1−cos2θ
cos2θ=1−sin2θ
sinθ=1−cos2θ
cosθ=1−sin2θ
sinθ=1−cosθ
31
Multiple Select
1+ tan2θ=sec2θ
Choose the equivalent equations?
tan2θ=sec2θ−1
tan2θ−sec2θ=1
sec2θ−tan2θ=1
tanθ=sec2θ−1
secθ=1+tanθ
32
Simplifying trigonometric expressions.
Using your resources
33
Multiple Choice
Exchange each term with an identity then use algebra to reduce:
secxtanx
cosx
cscx
cotx
sinx
34
35
Multiple Choice
Now try this one. Again reduce by substituting with identities:
(secx)(cotx)(sinx)
sin x
- sin x
1
-1
36
Simplifying Suggestions
Here are some common techniques for simplifying trig expressions
Notice you will be using algebra to help reduce
Let's look at more problems using these suggestions......
37
Multiple Choice
Reduce by substituting with identities:
tan x cotx −cos2x
tanx
cotx
sin2x
cos2x
38
39
Homework
Day 1
Page 354 – 355 # 1, 2, 7, 11, 13, 17, 21 – 25, 33 – 39 odd
40
Multiple Choice
Simplify by factoring out a GCF first. Look at what you have left. Can you replace with an identity?
cos3x+sin2xcosx
sinx
cosx
tanx
1
41
Multiple Choice
Distribute then exchange with identities:
sinx(secx−cscx)
1−tanx
tanx−1
1−cotx
sinx
42
Now you know the basics!
Tips for success:
Memorize the identities so you can recall them quickly!
Don't give up! There may be more than one way to simplify.
Keep practicing! You got this!
43
Multiple Choice
Substitute then find a common denominator so you can combine into 1 fraction: cosx+sinxtanx
csc x
sec x
1/sec x
cos x
44
Multiple Choice
Simplify by first splitting into 2 fractions: (Note: you CANNOT cross out anything until you've done this!)
sinxcosxcosx−sinx
cscx−secx
1
0
secx−cscx
45
46
47
PreCalculus
Section 5.1 Part 1
Using Fundamental Identities

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