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HPC Section 5.1 Part 1

HPC Section 5.1 Part 1

Assessment

Presentation

Mathematics

9th - 12th Grade

Medium

CCSS
HSG.SRT.C.8, HSG.SRT.C.6, HSF.TF.C.8

Standards-aligned

Created by

Shane Devlin

Used 11+ times

FREE Resource

18 Slides • 28 Questions

1

HPC Section 5.1 Part 1

​Using Fundamental Identities

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2

Multiple Select

Question image

Given the diagram, which of the following statements are true?

1

x2+y2=r2x^2+y^2=r^2

2

sinθ=yr\sin\theta=\frac{y}{r}

3

r=x+yr=x+y

4

sin2θ+cos2θ=1\sin^2\theta+\cos^2\theta=1

5

x=r2y2x=\sqrt{r^2-y^2}

3

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4

Identity Categories:

  • Reciprocal

  • Quotient

  • Pythagorean

  • Sum & Difference

  • Double Angle

  • Half Angle

  • For this part of our unit, we will be discussing Reciprocal, Quotient and Pythagorean Identities **MEMORIZE THEM!

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5

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6

Multiple Choice

Question image

 Which of the following would be the definition of

cosθ\cos\theta  ?

1

xy\frac{x}{y}  

2

xr\frac{x}{r}  

3

yr\frac{y}{r}  

4

rx\frac{r}{x}  

5

ry\frac{r}{y}  

7

Multiple Choice

Question image

 Which of the following would be the definition of
cotθ\cot\theta  ?

1

xy\frac{x}{y}  

2

xr\frac{x}{r}  

3

yr\frac{y}{r}  

4

rx\frac{r}{x}  

5

ry\frac{r}{y}  

8

Multiple Choice

Question image

 Which of the following would be the definition of
secθ\sec\theta  ?

1

xy\frac{x}{y}  

2

xr\frac{x}{r}  

3

yr\frac{y}{r}  

4

rx\frac{r}{x}  

5

ry\frac{r}{y}  

9

Multiple Choice

Question image

 Which of the following would be the definition of
cscθ\csc\theta  ?

1

xy\frac{x}{y}  

2

xr\frac{x}{r}  

3

yr\frac{y}{r}  

4

rx\frac{r}{x}  

5

ry\frac{r}{y}  

10

Reciprocal Identities: 

11

Quotient Identities:

12

Multiple Choice

Question image
*
1
sin x
2
cos x
3
csc x
4
cot x

13

Multiple Choice

Question image
*
1
csc x
2
sec x
3
cot x
4
tan x

14

Multiple Choice

Question image
*
1
cos x
2
csc x
3
sec x
4
cot x

15

Multiple Choice

Question image
*
1
csc x
2
sec x
3
cot x
4
tan x

16

Multiple Choice

Question image
*
1
csc x
2
sec x
3
cot x
4
tan x

17

Pythagorean identity #1:

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18

Pythagorean Identity #2

19

Pythagorean Identity #3

20

Multiple Choice

Rearrange:  sin2x+cos2x=1\sin^2x+\cos^2x=1  to solve for:   sin2x\sin^2x   

1

sin2x=1cos2x\sin^2x=1-\cos^2x  

2

sin2x=1+cos2x\sin^2x=1+\cos^2x  

3

sin2x=cos2x1\sin^2x=\cos^2x-1  

21

Multiple Choice

Rearrange:  sin2x+cos2x=1\sin^2x+\cos^2x=1  to solve for  cos2x\cos^2x  

1

cos2x=1sin2x\cos^2x=1-\sin^2x  

2

cos2x=1+sin2x\cos^2x=1+\sin^2x  

3

cos2x=sin2x1\cos^2x=\sin^2x-1  

22

Multiple Choice

Rearrange to solve for tan2θ\tan^2\theta
                                        1 + tan2θ= sec2θ1\ +\ \tan^2\theta=\ \sec^2\theta  

1

tan2θ = sec2θ + 1

2

tan2θ = sec2θ - 1

3

tanθ = secθ - 1

4

tan2θ = opp/adj

23

Multiple Choice

Rearrange so it equals 1: 
                                        1 + tan2x= sec2x1\ +\ \tan^2x=\ \sec^2x  

1

tan2xsec2x=1\tan^2x-\sec^2x=1  

2

sec2xtan2x=1\sec^2x-\tan^2x=1  

3

sec2x+tan2x=1\sec^2x+\tan^2x=1  

4

tan2x1=sec2x\tan^2x-1=\sec^2x  

24

Multiple Choice

Solve the following for  cot2θ\cot^2\theta  :
1+cot2θ=csc2θ1+\cot^2\theta=\csc^2\theta  


1

1 = cot2θ + csc2θ

2

cot2θ =1 - csc2θ

3

cot2θ = csc2θ -1

4

cot2θ = adj/opp

25

IN CASE YOU DIDN'T GET THEM....HERE ARE ALL THE PYTHAGOREAN ARRANGEMENTS!


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26

Multiple Select

sin2θ+cos2θ=1\sin^2\theta+\cos^2\theta=1  

Choose the equivalent equations?

1

sin2θ=1cos2θ\sin^2\theta=1-\cos^2\theta  

2

cos2θ=1sin2θ\cos^2\theta=1-\sin^2\theta  

3

sinθ=1cos2θ\sin^{ }\theta=\sqrt{1-\cos^2\theta}  

4

cosθ=1sin2θ\cos\theta=\sqrt{1-\sin^2\theta}  

5

sinθ=1cosθ\sin\theta=1-\cos\theta  

27

Multiple Select

1+ tan2θ=sec2θ1+\ \tan^2\theta=\sec^2\theta  

Choose the equivalent equations?

1

tan2θ=sec2θ1\tan^2\theta=\sec^2\theta-1  

2

tan2θsec2θ=1\tan^2\theta-\sec^2\theta=1  

3

sec2θtan2θ=1\sec^2\theta-\tan^2\theta=1  

4

tanθ=sec2θ1\tan\theta=\sqrt{\sec^2\theta-1}  

5

secθ=1+tanθ\sec\theta=1+\tan\theta  

28

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Simplifying trigonometric expressions.

Using your resources

29

Multiple Choice

Exchange each term with an identity then use algebra to reduce:

  tanxsecx\frac{\tan x}{\sec x}

1

cosx\cos x  

2

cscx\csc x  

3

cotx\cot x  

4

sinx \sin x\  

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31

Multiple Choice

Now try this one.  Again reduce by substituting with identities:
(secx)(cotx)(sinx)\left(\sec x\right)\left(\cot x\right)\left(\sin x\right)

1

sin x

2

- sin x

3

1

4

-1

32

Simplifying Suggestions

  • Here are some common techniques for simplifying trig expressions

  • Notice you will be using algebra to help reduce

  • Let's look at more problems using these suggestions......

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33

Multiple Choice

Reduce by substituting with identities:

tan x cotx cos2x\tan\ x\ \cot x\ -\cos^2x  

1

tanx

2

cotx

3

sin2x

4

cos2x

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35

Multiple Choice

Simplify by factoring out a GCF first. Look at what you have left.  Can you replace with an identity?

cos3x+sin2xcosx\cos^3x+\sin^2x\cos x

1

sinx\sin x  

2

cosx\cos x  

3

tanx\tan x  

4

1

36

Multiple Choice

Distribute then exchange with identities:
sinx(secxcscx)\sin x\left(\sec x-\csc x\right)

1

1tanx1-\tan x  

2

tanx1\tan x-1  

3

1cotx1-\cot x  

4

sinx\sin x  

37

Multiple Choice

Use

cscx=2\csc x=2

find the other trig functions.  sin x = ?

1

12\frac{1}{2}  

2

32\frac{\sqrt{3}}{2}  

3

233\frac{2\sqrt{3}}{3}  

4

3\sqrt{3}  

5

33\frac{\sqrt{3}}{3}  

38

Multiple Choice

Use

cscx=2\csc x=2  

find the other trig functions.  If x is in the first quadrant what is cos x = ?

1

12\frac{1}{2}  

2

32\frac{\sqrt{3}}{2}  

3

233\frac{2\sqrt{3}}{3}  

4

3\sqrt{3}  

5

33\frac{\sqrt{3}}{3}  

39

Multiple Choice

Use

cscx=2\csc x=2  

find the other trig functions.  If x is in the first quadrant what is sec x = ?

1

12\frac{1}{2}  

2

32\frac{\sqrt{3}}{2}  

3

233\frac{2\sqrt{3}}{3}  

4

3\sqrt{3}  

5

33\frac{\sqrt{3}}{3}  

40

Multiple Choice

Use

cscx=2\csc x=2

 find the other trig functions.  If x is in the first quadrant what is tan x = ?

1

12\frac{1}{2}  

2

32\frac{\sqrt{3}}{2}  

3

233\frac{2\sqrt{3}}{3}  

4

3\sqrt{3}  

5

33\frac{\sqrt{3}}{3}  

41

Now you know the basics!

  • Tips for success:

  • Memorize the identities so you can recall them quickly!

  • Don't give up! There may be more than one way to simplify.

  • Keep practicing! You got this!

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42

Multiple Choice

Substitute then find a common denominator so you can combine into 1 fraction:              cosx+sinxtanx\cos x+\sin x\tan x  

1

csc x

2

sec x

3

1/sec x

4

cos x

43

Multiple Choice

Simplify by first splitting into 2 fractions: (Note:  you CANNOT cross out anything until you've done this!)

cosxsinxsinxcosx\frac{\cos x-\sin x}{\sin x\cos x}  

1

cscxsecx\csc x-\sec x  

2

1

3

0

4

secxcscx\sec x-\csc x  

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46

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HPC Section 5.1 Part 1

​Using Fundamental Identities

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