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M2T3 - Review - Part I

M2T3 - Review - Part I

Assessment

Presentation

Mathematics

8th - 9th Grade

Medium

CCSS
8.EE.C.8B, 8.EE.C.8C, HSA.CED.A.3

+1

Standards-aligned

Created by

Christopher Beach

Used 11+ times

FREE Resource

9 Slides • 11 Questions

1

M2T3 - Review

Part I

Systems of Linear Equations

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2

Systems of Linear Equations

  • Solution = Intersection

  • One solution, no solution, and infinite many solutions

  • Solving methods: graphing, substitution, and linear combination

3

Solutions

The solution to a system of linear equations is the intersection between the lines of those equations. This is when all of the equations simultaneously share an input and an output.

4

Solutions

Systems of linear equations can have the following numbers of solutions:


- One solution - lines with different slopes will intersect once across their domains


- No solution - Parallel lines (same slope, different y-intercept) will never intersect, and therefore, have no solution


- Infinite many solutions - Equations of the same lines will intersect at ALL TIMES across their entire domain, and therefore, have infinite many soltuions

5

Methods of Solving

- Graphing - We can graph the lines of systems of equations to find their intersection point

6

Multiple Choice

Solve:
-2x + 5y = -1
4x - 2y = -6
1
(-2, -1)
2
(2, 7)
3
(3, 1)
4
(-1, -2)

7

Multiple Choice

Solve the system of equations.
y = 4x+1
3x + 2y = 13
1
(1, 5)
2
(5, 1)
3
(0.25, 2)
4

8

Methods of Solving

- Substitution - We can isolate a variable to substitute an express into another equation to solve for the remaining variable

9

Multiple Choice

Solve the system of equations.
y = 4x+1
3x + 2y = 13
1
(1, 5)
2
(5, 1)
3
(0.25, 2)
4

10

Multiple Choice

Solve the following system using any method.

y = 2x + 1

y = 4x - 1

1

(1,3)

2

(-1,-3)

3

(-1,3)

4

(3,1)

11

Multiple Choice

Solve the following system using any method.

y = 2/3x - 2

y = -x + 3

1

(0,3)

2

(0,-3)

3

(3,0)

4

(-3,0)

12

Methods of Solving

- Linear Combination/Elimination - We can re-write equations to produce additive inverses of a variable to eliminate a variable, which allows us to solve for the remaining variable

13

Multiple Choice

Solve the following system using any method.

y = 2x + 1

y = 4x - 1

1

(1,3)

2

(-1,-3)

3

(-1,3)

4

(3,1)

14

Multiple Choice

Solve the following system using any method.

3x + 2y = 16

7x + y = 19

1

(-2,5)

2

(-2,-5)

3

(2,-5)

4

(2,5)

15

Methods of Solving

- Once we have identified the solution to one of our variables, we can substitute that solution into one of our equations to solve for the remaining variable

16

Multiple Choice

A large pizza at Palanzio’s Pizzeria costs $6.80 plus $0.90 for each topping. The cost of a large cheese pizza at Guido’s Pizza is $7.30 plus $0.65 for each topping. Which system of equations could be used to find the number of toppings when both companies cost the same amount? 
1
y = 6.80 + .65x
y=7.30+.90x
2
x + y = 6.80
x + y = 7.30
3
y = 6.80+.90x
y = 7.30 + .65x
4
y + .90x = 6.80
y + .65x = 7.30

17

Multiple Choice

Your family goes to a restaurant for dinner. There are people in your family. Some order the chicken dinner for $14.80, and some order steak for $17. If the total bill was $91, which system best represents the situation? 
1
x + y = 6
14.80x + 17y = 91
2
x + y = 91
14.80x + 17y = 6
3
x + y = 6
14.80y + 17x = 91
4
x + y = 91
14.80x+ 17y = 6

18

Multiple Choice

Last season two running backs on the Steelers football team rushed a combined total of 1550 yards.  One rushed 4 times as many yards as the other.  Let x and y represent the number of yards each individual player rushed. Which system of equations could be used? 
1
x + y = 1550
y  = 4x
2
x + y = 1550
y = x + 4
3
y - x = 1550
y = 4x
4
y = 1550 + x
y = x + 4

19

Multiple Choice

Nancy went to the grocery story.  On Monday she purchased 4 apples and 6 bananas for a total of $13.  On Wednesday she purchased 3 apples and 7 bananas for a total of $13.50.  Which system of equations represents the situation?
1
4x + 6y = 3
13.5x - 13y = 6
2
x + y = 4
x - y = 6
3
4x + 6y = 13
3x + 7y = 13.5
4
4x - 6y = 13
3x - 7y = 13.5

20

Questions?

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M2T3 - Review

Part I

Systems of Linear Equations

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