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solving trigonometric equations

solving trigonometric equations

Assessment

Presentation

•

Mathematics

•

10th Grade

•

Practice Problem

•

Medium

•
CCSS
HSF.TF.B.7, HSA-REI.B.4B

Standards-aligned

Created by

ahmed atef

Used 13+ times

FREE Resource

4 Slides • 10 Questions

1

solving trigonometric equations

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2

Poll

What is the zero product property?

I know and I can explain it

I heard it before

never heard of it

3

Poll

What is factoring?

I know and i can explain it

i heard about it

never heard of it before

4

Poll

What is the quadratic formula

I heard about it and can explain it

i heard about it

never heard about it

5

Solving by factoring

  • When trigonometric functions cannot be combined on one side of an equation, try factoring and applying the zero product property

  • If the equation has quadratic form, factor if possible. If not possible, apply the quadratic Formula

6

Let's see an example

 cos⁡x⋅sin⁡x=3cos⁡x\cos x\cdot\sin x=3\cos x  

7

Multiple Choice

Whats our first step to solve  cos⁡xsin⁡x=3cos⁡x\cos x\sin x=3\cos x  

1

 cos⁡xsin⁡x−3cos⁡x=0\cos x\sin x-3\cos x=0  

2

 cos⁡xsin⁡x3cos⁡x=0\frac{\cos x\sin x}{3\cos x}=0  

8

BE CAREFUL

we CAN NOT cancel  cos⁡ x\cos\ x  in the expression  cos⁡x sin⁡xcos⁡x=0\frac{\cos x\ \sin x}{\cos x}=0  




why?

9

Multiple Select

 cos⁡x sin⁡x−3cos⁡x=0\cos x\ \sin x-3\cos x=0  

Factor and solve (check all possible answers)

1

 π\pi  

2

 π2\frac{\pi}{2}  

3

 3π2\frac{3\pi}{2}  

4

0

5

no solution

10

Multiple Select

you do it! solve and check all possible solutions


 2sin⁡x cos⁡x =2cos⁡ x2\sin x\ \cos x\ =\sqrt{2}\cos\ x  

1

 π2\frac{\pi}{2}  

2

 π4\frac{\pi}{4}  

3

 3π4\frac{3\pi}{4}  

4

 3π2\frac{3\pi}{2}  

11

Poll

 cos⁡4x+cos⁡2x−2=0\cos^4x+\cos^2x-2=0  

how will we solve this question

factoring

quadratic formula

12

Multiple Select

check all the solutions to

 x2+x−2=0x^2+x-2=0  


1

0

2

-2

3

2

4

1

13

Multiple Select

What are the solutions to (cos⁡2x)2+cos⁡2x−2=0\left(\cos^2x\right)^2+\cos^2x-2=0  


1

0

2

 π2\frac{\pi}{2}  

3

 π\pi  

4

2  π\pi  

14

Multiple Select


challenge question (check all answers)
 4cos⁡2x+2cos⁡x−22cos⁡x=24\cos^2x+2\cos x-2\sqrt{2}\cos x=\sqrt{2}  


1

 4π3\frac{4\pi}{3}  

2

 π4\frac{\pi}{4}  

3

 π3\frac{\pi}{3}  

4

 7π4\frac{7\pi}{4}  

5

 2π3\frac{2\pi}{3}  

pattern-tertiary

solving trigonometric equations

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