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Summation of A.S.

Summation of A.S.

Assessment

Presentation

Mathematics

11th Grade

Hard

Created by

Kin Bon Poon

Used 3+ times

FREE Resource

21 Slides • 8 Questions

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Summation of A.S.

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Multiple Choice

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I only

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II only

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I and III only

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I, II and III

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Multiple Choice

Evaluate 13 + 9 + 5 + ... + 14th term.

1

 142[13+(141)(4)]\frac{14}{2}\left[13+\left(14-1\right)\left(-4\right)\right]  

2

 142[2(13)+(141)(4)]\frac{14}{2}\left[2\left(13\right)+\left(14-1\right)\left(-4\right)\right]  

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 142[13+(141)(4)]\frac{14}{2}\left[13+\left(14-1\right)\left(4\right)\right]  

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 142[2(13)+(141)(4)]\frac{14}{2}\left[2\left(13\right)+\left(14-1\right)\left(4\right)\right]  

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 13+(141)(4)13+\left(14-1\right)\left(-4\right)  

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Multiple Select

Evaluate 13 + 9 + 5 + ... + (-399).


(There may be more than 1 answer.)

1

 1042[13+(399)]\frac{104}{2}\left[13+\left(-399\right)\right]  

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 1032[2(13)+(399)]\frac{103}{2}\left[2\left(13\right)+\left(-399\right)\right]  

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 1042[2(13)+(1041)(4)]\frac{104}{2}\left[2\left(13\right)+\left(104-1\right)\left(4\right)\right]  

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 1032[2(13)+(1031)(4)]\frac{103}{2}\left[2\left(13\right)+\left(103-1\right)\left(4\right)\right]  

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Multiple Select

Evaluate 13 + 9 + 5 + ... + (-3999).


(There may be more than 1 answer.)

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 10042[13+(3999)]\frac{1004}{2}\left[13+\left(-3999\right)\right]  

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 10042[2(13)+(3999)]\frac{1004}{2}\left[2\left(13\right)+\left(-3999\right)\right]  

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 10042[2(13)+(10041)(4)]\frac{1004}{2}\left[2\left(13\right)+\left(1004-1\right)\left(-4\right)\right]  

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 10042[13+(10041)(4)]\frac{1004}{2}\left[13+\left(1004-1\right)\left(-4\right)\right]  

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-2000972

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Multiple Select

Evaluate 5 + 9 + 13 + ... + 101th term.


(There may be more than 1 answer.)

1

 1012[5+(1011)(4)]\frac{101}{2}\left[5+\left(101-1\right)\left(4\right)\right]  

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 1012[2(5)+(1011)(4)]\frac{101}{2}\left[2\left(5\right)+\left(101-1\right)\left(4\right)\right] 

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20705

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 1012(5+400)\frac{101}{2}\left(5+400\right)  

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20452.5

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Multiple Select

Evaluate 5 + 9 + 13 + ... + 101.


(There may be more than 1 answer.)

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 252[2(5)+(251)(4)]\frac{25}{2}\left[2\left(5\right)+\left(25-1\right)\left(4\right)\right]  

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 1012[2(5)+(1011)(4)]\frac{101}{2}\left[2\left(5\right)+\left(101-1\right)\left(4\right)\right] 

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 1012(5+101)\frac{101}{2}\left(5+101\right)  

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 252(5+101)\frac{25}{2}\left(5+101\right)  

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1325

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Multiple Select

Find the sum of all positive terms of the A.S. 999, 904, 809, ...


(There may be more than 1 answer.)

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 112(999+49)\frac{11}{2}\left(999+49\right)  

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 122(99946)\frac{12}{2}\left(999-46\right)  

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 122[2(999)+(121)(95)]\frac{12}{2}\left[2\left(999\right)+\left(12-1\right)\left(-95\right)\right]  

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 112[999+(111)(95)]\frac{11}{2}\left[999+\left(11-1\right)\left(-95\right)\right]  

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6288

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Poll

How much do you understand today?

0%-19.9%

20%-39.9%

40%-59.9%

60%-79.9%

80%-100%

Summation of A.S.

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