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Review Parallel and Perpendicular Lines

Review Parallel and Perpendicular Lines

Assessment

Presentation

Mathematics

9th Grade

Medium

Created by

Sherri Morrisey

Used 40+ times

FREE Resource

3 Slides • 7 Questions

1

Review Parallel and Perpendicular Lines

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2

Parallel Lines

Parallel lines have the same slope.

Remember the point-slope formula is:

y - y1= m(x - x1)

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3

Writing a line perpendicular to a given line


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4

Multiple Choice

 y=23x1y=-\frac{2}{3}x-1  

Write an equation of a line that is perpendicular to the given equation above and passes through point (4, 3)



What would be the NEW perpendicular slope to use when writing a new equation?  

1

 23-\frac{2}{3}  

2

 32\frac{3}{2}  

3

 32-\frac{3}{2}  

4

 23\frac{2}{3}  

5

Multiple Choice

 y=23x1y=-\frac{2}{3}x-1  

Write an equation of a line that is perpendicular to the given equation above and passes through point (4, 3)



Which is the correct process for plugging in writing the new equations?

1

y- 4 =  23\frac{2}{3}  (x - 3)

2

 y+4=32(x+3)y+4=\frac{3}{2}\left(x+3\right)  

3

 y3=32(x4)y-3=-\frac{3}{2}\left(x-4\right)  

4

 y4=32(x3)y-4=\frac{3}{2}\left(x-3\right)  

6

Multiple Choice

 y=23x1y=-\frac{2}{3}x-1  

Write an equation of a line that is perpendicular to the given equation above and passes through point (4, 3)



After using the point-slope formula to write a new equation, what would be the next s

1

 23-\frac{2}{3}  

2

 32\frac{3}{2}  

3

 32-\frac{3}{2}  

4

 23\frac{2}{3}  

7

Multiple Choice

Which of the following represents the equation of the line passing through (-4, 5) PERPENDICULAR to the line y = -1/2x + 5/2? Write your answer in point-slope form

1

y - 5 = 2(x + 4)

2

y - 5 = -1/2(x + 4)

3

y - 5 = 5/2(x + 4)

4

y - 5 = -2/5(x + 4)

8

Multiple Choice

The equation of Line J is written as

 y=9x+95y=9x+\frac{9}{5}  Line H is perpendicular to Line J and passes through the point (8, 2)\left(-8,\ 2\right) 

1

 y=19+269y=-\frac{1}{9}+\frac{26}{9}  

2

 y=9x+74y=9x+74  

3

 y=9x70y=9x-70  

4

 y=19x+109y=-\frac{1}{9}x+\frac{10}{9}  

9

Fill in the Blank

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10

Multiple Choice

The equation of Line J is written as

 y=9x+95y=9x+\frac{9}{5}  Line H is perpendicular to Line J and passes through the point (8, 2)\left(-8,\ 2\right) 

1

 y=19+269y=-\frac{1}{9}+\frac{26}{9}  

2

 y=9x+74y=9x+74  

3

 y=9x70y=9x-70  

4

 y=19x+109y=-\frac{1}{9}x+\frac{10}{9}  

Review Parallel and Perpendicular Lines

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