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QUADRATIC EQUATION - NATURE OF ROOTS

QUADRATIC EQUATION - NATURE OF ROOTS

Assessment

Presentation

Mathematics

9th - 10th Grade

Hard

Created by

LAKSHYA Sunil Sharma

Used 7+ times

FREE Resource

12 Slides • 22 Questions

1

QUADRATIC EQUATION - NATURE OF ROOTS

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2

For a quadratic equation ax2 + bx + c = 0 , D = b2 - 4ac is called the discriminant.

  • IF D > 0 & then the roots are real and distinct.

  • IF D = 0 & then the roots are real and equal.

  • IF D < 0 & then the roots are not real.

3

NATURE OF ROOTS

  • IF D > 0 & D is a perfect square then two roots are rational

4

NATURE OF ROOTS

  • IF D > 0 & D is not a perfect square then two roots are irrational

5

Multiple Choice

If the roots of x² - 5x + a = 0 are equal, then a =

1

254\frac{25}{4}

2

±254\pm\frac{25}{4}

3

254-\frac{25}{4}

4

none of the above

6

Multiple Choice

If the roots of px² + qx + 1 = 0 are equal, then

1

q² - 4p = 0

2

q² + 4p = 0

3

p² - 4p = 0

4

p² + 4q = 0

7

Multiple Choice

If the roots 3x² + kx + 12 = 0 are equal, then k =

1

± 12

2

12

3

-12

4

0

8

Multiple Choice

The roots of the quadratic equation x² - 6x + 10 = 0 are

1

equal

2

not real

3

irrational

4

real

9

Multiple Choice

The quadratic equation 4x2 + 8x - (2p - 1) = 0 has real roots.

What is the range of values of p?

1

p>32p>-\frac{3}{2}

2

p<32p<-\frac{3}{2}

3

p32p\ge-\frac{3}{2}

4

p32p\le-\frac{3}{2}

10

Multiple Choice

 If x2+5px+16=0 has no real roots, thenIf\ x^2+5px+16=0\ has\ no\ real\ roots,\ then  

1

 p>85p>\frac{8}{5}  

2

 85<p<85-\frac{8}{5}<p<\frac{8}{5}  

3

 p<85p<-\frac{8}{5}  

4

none of the above

11

Multiple Choice

For ax2+ bx + c = 0, which of the following statement is wrong?

1

If b2 – 4ac is a perfect square, the roots are rational.

2

If b2 = 4ac , the roots are real and equal.

3

If b2 – 4ac is negative, no real roots exist.

4

If b2 = 4ac , the roots are real and unequal.

12

Multiple Choice

The roots of the equation 9x2bx + 81 = 0 will be equal, if the value of b is

1

± 9

2

± 18

3

± 27

4

± 54

13

Multiple Choice

Which of the following has real roots?

1

x2 + 23x 1 =0x^2\ +\ 2\sqrt{3}x\ -\ 1\ =0

2

x2 + 2x + 4 = 0x^2\ +\ 2x\ +\ 4\ =\ 0

3

x2 x + 1 = 0x^2\ -\ x\ +\ 1\ =\ 0

4

3x2 2x + 2 = 03x^2\ -\ 2x\ +\ 2\ =\ 0

14

Multiple Choice

If px2 + qx + r = 0 has equal roots, value of r will be

1

q24p\frac{q^2}{4p}

2

q24p-\frac{q^2}{4p}

3

4pq2\frac{4p}{q^2}

4

none of these

15

Multiple Choice

Positive value of p for which equation x2 + px + 64 = 0 and x2 – 8x + p = 0 will both have equal roots will be

1

p ≥ 16

2

p ≤ 16

3

p = 16

4

none of these

16

Multiple Choice

Write the quadratic equations whose roots have the given sum and product, sum = - 8, product = 5.

1

x2 +8x + 5 = 0x^2\ +8x\ +\ 5\ =\ 0

2

x2 8x 5 = 0x^2\ -\ 8x\ -\ 5\ =\ 0

3

x2 8x + 5 = 0x^2\ -\ 8x\ +\ 5\ =\ 0

4

x2 + 5x 8 = 0x^2\ +\ 5x\ -\ 8\ =\ 0

17

Multiple Choice

Find the value of k so that the equation kx^2\ -\ 24x\ +\ 16\ =\ 0  has one real root.

1

-9

2

9

3

18

4

-18

18

Multiple Select

Determine the sum and product of the roots given the quadratic equation 13x2 -26x +39 = 0.

1

S: -2 and P: -3

2

S: 2 and P: -3

3

S: -2 and P: 3

4

S: 2 and P: 3

19

Multiple Select

Write the quadratic equation whose roots are

 25 and 25-2\sqrt{5}\ and\ 2\sqrt{5}  .

1

 x25x4=0x^2-\sqrt{5}x-4=0  

2

 x2+5x+4=0x^2+\sqrt{5}x+4=0  

3

 x24=0x^2-4=0  

4

 x220=0x^2-20=0  

20

Multiple Select

Write the quadratic equation whose roots are

 7and 7\sqrt{7}and\ -\sqrt{7}  .

1

 x2+49=0x^2+49=0  

2

 x249=0x^2-49=0  

3

 x27=0x^2-7=0  

4

 x2+7=0x^2+7=0  

21

Fill in the Blanks

Type answer...

22

Multiple Choice

What is the sum and product of the roots of x2 + 4x + 3 = 0?

1

sum = 4; product = 3

2

sum = - 4; product = 3

3

sum = - 4; product = - 3

4

sum = 4; product = - 3

23

Multiple Choice

What is the PRODUCT of the roots of the quadratic equation x2 - 5x + 6 = 0?

1

-5

2

-6

3

5

4

6

24

Multiple Choice

What is the SUM of the roots of the quadratic equation x2 - 5x + 6 = 0?

1

-5

2

-6

3

5

4

6

25

Multiple Choice

What is the formula in finding the PRODUCT of the roots of quadratic equation?

1

 ba\frac{-b}{a}  

2

 ca\frac{c}{a}  

26

Multiple Choice

What is the formula in finding the SUM of the roots of quadratic equation?

1

 ba\frac{-b}{a}  

2

 ca\frac{c}{a}  

27

Common new roots

 +1 , β+1\cdot\propto+1\ ,\ \beta+1  
 x, xβ\cdot\frac{x}{\propto},\ \frac{x}{\beta}  where x is a constant 
 1 , β1\cdot\propto-1\ ,\ \beta-1  
 1, 1β\cdot\frac{1}{\propto},\ \frac{1}{\beta}  
 β, β\cdot\frac{\propto}{\beta},\ \frac{\beta}{\propto}  

28

New Roots

Steps:

1. State coefficients a,b,c .
2. Find  +β, β\propto+\beta,\ \propto\beta  
3. For new roots find: sum of roots and product of roots.
4. Substitute  +β, β \propto+\beta,\ \propto\beta\   from step 2 into  x2(sum)x+ product =0x^2-\left(sum\right)x+\ product\ =0  
N.B your answer will be a quadratic equation.

29

Examples of the different operations.

If  and β\propto and\ \beta  are the roots of the equation  x23x18=0x^2-3x-18=0  find:

 a.  +β    b.β    c.2β2   d.2β+β2 \propto+\beta\ \ \ \ b.\propto\beta\ \ \ \ c.\propto^2\beta^2\ \ \ d.\propto^2\beta+\beta^2\propto\  

 a) +β=ba=(3)1=3\propto+\beta=\frac{-b}{a}=\frac{-\left(-3\right)}{1}=3  

b) β=ca=181=18\propto\beta=\frac{c}{a}=\frac{-18}{1}=-18  

c)  2β2(β)2=(18)2=324\propto^2\beta^2\Longrightarrow\left(\propto\beta\right)^2=\left(-18\right)^2=324  
d)  2β+β2β(+β)=18(3)=54\propto^2\beta+\beta^2\propto\Longrightarrow\propto\beta\left(\propto+\beta\right)=-18\left(3\right)=-54  

30

Operations with alpha and beta.

1.  +β=ba\propto+\beta=\frac{-b}{a}    
2.  β=ca\propto\beta=\frac{c}{a}  
3.  2β2=(β)2\propto^2\beta^2=\left(\propto\beta\right)^2  
4.  2β+β2=β(+β)\propto^2\beta+\beta^2\propto=\propto\beta\left(\propto+\beta\right)  
5. x+xβ=x+xββ=x(+β)β\frac{x}{\propto}+\frac{x}{\beta}=\frac{x\propto+x\beta}{\propto\beta}=\frac{x\left(\propto+\beta\right)}{\propto\beta}  where x is a constant (e.g 2,3,4,5)

6.  (+β)2=squared of +β\left(\propto+\beta\right)^2=squared\ of\ \propto+\beta  
7.  β+β=2+β2β= (+β)22ββ\frac{\propto}{\beta}+\frac{\beta}{\propto}=\frac{\propto^2+\beta^2}{\propto\beta}=\ \frac{\left(\propto+\beta\right)^2-2\propto\beta}{\propto\beta}  

31

Example 2.

If  and \propto and\   are the roots of the equation  2x25x+3=02x^2-5x+3=0  find:

 1.  +β\propto+\beta   2.  β\propto\beta  


 2x25x+3=02x^2-5x+3=0  
 a=2  b=5  c=3a=2\ \ b=-5\ \ c=3  

 +β=ba=(5)2=52\propto+\beta=\frac{-b}{a}=\frac{-\left(-5\right)}{2}=\frac{5}{2}  
 β=ca=32\propto\beta=\frac{c}{a}=\frac{3}{2}  

32

example 1.

If  x22x8=0 has rootsand βx^2-2x-8=0\ has\ roots\propto and\ \beta  find: a. +β  b.β\propto+\beta\ \ b.\propto\beta  



 x23x8=0x^2-3x-8=0  
 a=1  b=2  c=8a=1\ \ b=-2\ \ c=-8  

a)  +β=ba=(2)1=21=2\propto+\beta=\frac{-b}{a}=\frac{-\left(-2\right)}{1}=\frac{2}{1}=2  
b)  β=ca=81=8\propto\beta=\frac{c}{a}=\frac{-8}{1}=-8  

33

Representation of the relationships.

Find the values of x if  x2+4x12=0x^2+4x-12=0  

 x2+4x12=0x^2+4x-12=0  (factorize)
 (x+6)(x2)=0\left(x+6\right)\left(x-2\right)=0  
 x=6 or x=2\therefore x=-6\ or\ x=2  

Let roots be   & β\propto\ \&\ \beta  
 =6  β=2\propto=-6\ \ \beta=2           Sum of Roots :   +β=6+2=4\propto+\beta=-6+2=-4                                                   Product of Roots :  β=6(2)=12\propto\beta=-6\left(2\right)=-12  
Therefore the relationship between the roots and coefficients is   +β=ba  &  β=ca\propto+\beta=\frac{-b}{a}\ \ \&\ \ \propto\beta=\frac{c}{a}  

34

Roots And Coefficients

 ax2+bx+c=0ax^2+bx+c=0  
The coefficients are a, b and c.

  β\propto\ \beta  - these are called roots
  alpha   βbeta\propto-\ alpha\ \ \ \beta-beta  
Note: the symbol for alpha can also be represented by  α\alpha  

There are relationships between coefficients of a quadratic equation and the roots alpha and beta. The relationship is based on the Sum of the Roots and the Product of the roots.

QUADRATIC EQUATION - NATURE OF ROOTS

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