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Quadratics Day 2

Quadratics Day 2

Assessment

Presentation

Mathematics

8th - 12th Grade

Medium

Created by

Bette Horsington

Used 10+ times

FREE Resource

9 Slides • 13 Questions

1

Quadratics Day 2

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Multiple Choice

 x225=0x^2-25=0  Solve for x:

1

 ±25\pm25  

2

 2525  

3

 ±5\pm5  

4

 55  

5

Multiple Choice

 16x29=016x^2-9=0  solve for x:

1

 916\frac{9}{16}  

2

 ±34\pm\frac{3}{4}  

3

 ±43\pm\frac{4}{3}  

4

 169\frac{16}{9}  

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Multiple Choice

 (x1)2=36\left(x-1\right)^2=36  solve for x:

1

 7,57,-5  

2

 7, 5-7,\ 5  

3

 3737  

4

 3535  

8

Multiple Choice

 2(x3)2=322\left(x-3\right)^2=32  : solve for x

1

 1, 7-1,\ 7  

2

 19, 1319,\ -13  

3

 ±32\pm\sqrt{32}  

4

 3±323\pm\sqrt{32}  

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Multiple Choice

 x2+49=0x^2+49=0  Solve for x:

1

 ±49\pm49  

2

 ±i49\pm i49  

3

 ±7\pm7  

4

 ±7i\pm7i  

11

Multiple Choice

 (x5)2=81\left(x-5\right)^2=-81  solve for x

1

 ±9i\pm9i  

2

 5±9i-5\pm9i  

3

 5±9i5\pm9i  

4

 5±81i5\pm81i  

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Multiple Choice

What value of c would make this a perfect square trinomial?
x- 12x + c
1
36
2
24
3
144
4
-36

14

Multiple Choice

Complete the Square
x2 - 12x
1
(x + 6)2 + 12
2
(x - 6)2 - 24
3
(x - 6)2 - 12
4
(x - 6)2 - 36

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Multiple Choice

What value of c would make this a perfect sqaure trinomial?
x2 +8x + c
1
4
2
16
3
64
4
-16

17

Multiple Choice

Complete the Square
x2 + 6x + 5
1
(x + 3)2 - 4
2
(x + 6)2 - 4
3
(x + 3x)2 - 4
4
(x + 3)2 + 9

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Multiple Choice

Solve
x2 + 2x - 24 = 0
1
x = -6, x = 4
2
x = 6, x = -4
3
x = 12, x = -2
4
x = 8, x = -3

21

Multiple Choice

Solve 

(x −11)(5x + 1) = 0

1

x = 11 or x = 15-\frac{1}{5}

2

x = −11 or x = 15-\frac{1}{5}

3

x = 11 or x = 15\frac{1}{5}

4

x = −11 or x = 15\frac{1}{5}

22

Poll

On a scale of 1 to 5, How are you feeling about solving quadratics? (1 = totally confused, 5 = I completely understand)

1

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5

Quadratics Day 2

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