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Asymptote Review

Asymptote Review

Assessment

Presentation

Mathematics

9th - 12th Grade

Practice Problem

Medium

CCSS
HSF-IF.C.7D

Standards-aligned

Created by

Cat Harpham

Used 79+ times

FREE Resource

12 Slides • 4 Questions

1

Asymptote Review

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2

Degree of a function

highest exponent

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3

Leading Coefficient

number in front of the highest exponent

4

Rational functions

-can have horizontal, oblique, and vertical asymptotes

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5

Vertical Asympotes

the "invisible" vertical lines that a function can NEVER cross


Vertical Asymptotes cut the function into pieces

6

How to find the vertical asymptote when given only a function?

  • set the denominator equal to 0

  • solve for x

7

For Example: Find the vertical asymp. from the example shown

  • set denominator equal to 0:   x - 4 = 0

  • solve for x:    x  =  4

  • Thus there is a vertical asymptote at x = 4

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8

Fill in the Blank

 f(x)=x+5x6f\left(x\right)=\frac{x+5}{x-6}  ; Find the vertical asymptote

9

Factoring the denominator

  • When I set the denominator equal to 0 I run into a problem

  • How do I solve when it is x squared?

  • FACTOR!  x (x  -  3)

  • then set each factor equal to 0:   x = 0 and x = 3

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10

Fill in the Blank

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Find the vertical asymptotes by factoring

11

Horizontal Asymptotes

Invisible horizontal lines that a function can SOMETIMES cross



Horizontal asymptotes force the function to end a certain way

12

How to find the horizontal asymptote when given only a function?

  • There are 3 rules when finding horizontal asymptotes

  • 1.  If the degree of the numerator is greater than the degree of the denominator; then there are NO HORIZONTAL ASYMPTOTES

  • 2.  If the degree of the numerator is less than the degree of the denominator; then the horizontal asymptote MUST EXIST AT Y = 0

  • 3.  If the degree of the numerator is equal to the degree of the denominator; then the horizontal asymptote is the ratio of the leading coefficients

13

Ex. 2 Find the Horizontal Asymptotes

  • The degree of the numerator is 0

  • The degree of the denominator is 2

  • The den > num: therefore there is a horizontal asymptote at y = 0

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14

Ex. 3 Find the Horizontal asymptote

  • the degree of the numerator is 1

  • the degree of the denominator is 1

  • Since the degrees are equal the horizontal asymptote is at y = 1/2

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15

Multiple Choice

Find the horizontal asymptotes:

 f(x)=x44x16f\left(x\right)=\frac{x-4}{-4x-16}  

1

 y=4y=-4 

2

 y=4y=4  

3

 y =14y\ =\frac{-1}{4}  

4

 y =14y\ =\frac{1}{4}  

16

Multiple Choice

Find the horizontal asymptotes

 f(x)=x39x3x26x=9f\left(x\right)=\frac{x^3-9x}{3x^2-6x=9}  

1

 y=0y=0  

2

 y=3y=3  

3

 y=3y=-3  

4

DNE

Asymptote Review

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