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Application for Addition Formulae

Application for Addition Formulae

Assessment

Presentation

Mathematics

10th - 12th Grade

Easy

Created by

Joe Drauna

Used 2+ times

FREE Resource

4 Slides • 6 Questions

1

Application for Addition Formulae: Part 2

by J Drauna

2

​RECAP on Part 1

​To write the sum of a Sine/Cosine as a function using the Addition Formulae; You need to :

  1. ​Find the Modulus

  1. ​Find Alpha

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3

Multiple Choice

Question image

y = 2 sin θ+cosθy\ =\ 2\ \sin\ \theta+\cos\theta  

What is the modulus (R) of the above expression?

1

22  

2

55  

3

5\sqrt[]{5}  

4

11  

4

Poll

Question image

How difficult was it for you to find the modulus in the earlier question?

5

Multiple Choice

Question image

Which of the following is the correct expression for: R cos (θ+α)R\ \cos\ \left(\theta+\alpha\right)

 

1

sin θ  sinα + cosθ sinα\sin\ \theta\ \ \sin\alpha\ +\ \cos\theta\ \sin\alpha  

2

sin θcosα+cosθsinα\sin\ \theta\cos\alpha+\cos\theta\sin\alpha  

3

cosθcosαsinθsinα\cos\theta\cos\alpha-\sin\theta\sin\alpha  

4

cosθcosα+sinθsinα\cos\theta\cos\alpha+\sin\theta\sin\alpha  

6

Poll

Question image

After having equate both expressions correctly; it looks something like this. 2sinθ+cosθ=5cosθcosα5sinθsinα2\sin\theta+\cos\theta=\sqrt[]{5}\cos\theta\cos\alpha-\sqrt[]{5}\sin\theta\sin\alpha  

How confident are you in comparing the sine and cosine of θ\theta  ?

7

Multiple Choice

Question image

SO what are the correct comparisons for sin θ  \sin\ \theta\ \  and cosθ\cos\theta   for the function 2sinθ+cosθ=5cosθcosα5  sinθsinα2\sin\theta+\cos\theta=\sqrt[]{5}\cos\theta\cos\alpha-\sqrt[]{5}\ \ \sin\theta\sin\alpha  ?

1

2sinθ=5cosθcosα2\sin\theta=\sqrt[]{5}\cos\theta\cos\alpha     and cos θ=5sinθsinα\cos\ \theta=-\sqrt[]{5}\sin\theta\sin\alpha  

2

2 sin θ=5sinθsinα2\ \sin\ \theta=\sqrt[]{5}\sin\theta\sin\alpha   and cosθ=5cosθcosα\cos\theta=-\sqrt[]{5}\cos\theta\cos\alpha  

3

2sinθ=5sin θsinα2\sin\theta=-\sqrt[]{5}\sin\ \theta\sin\alpha    

and 

  cosθ=5cosθcosα\cos\theta=\sqrt[]{5}\cos\theta\cos\alpha  

8

​Solving ALPHA

Identify in what Quadrant would they share in common?

9

Multiple Choice

With sine being negative ;  sin α=25\sin\ \alpha=\frac{2}{-\sqrt[]{5}}   and cosine being positive;  cosα=15\cos\alpha=\frac{1}{\sqrt[]{5}}  , which Quadrant would they  both share ALPHA?

1

Quadrant 1

2

Quadrant 2

3

Quadrant 3

4

Quadrant 4

10

​TRUE VALUE OF ALPHA

Since both have in Quadrant 4;

Application for Addition Formulae: Part 2

by J Drauna

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