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Advance Algebra with Trigonometry, Section 2-1: Linear Equations in One Variable

Advance Algebra with Trigonometry, Section 2-1: Linear Equations in One Variable

Assessment

Presentation

Mathematics

12th Grade

Practice Problem

Medium

CCSS
8.EE.C.7B

Standards-aligned

Created by

Jeremy Adelmann

Used 9+ times

FREE Resource

8 Slides • 9 Questions

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Advance Algebra with Trigonometry

​Section 2-1: Linear Equations in One Variable

by Jeremy Adelmann

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​Section 2-1 Objectives

​​Students will be able to:

  • ​Decide whether a number is a solution of a linear equation.

  • ​Solve linear equations by using the addition and multiplication properties of equality.

  • ​Solve linear equations by using the distributive property.

  • ​Solve linear equations with fractions or decimals.

  • ​Identify conditional equations, contradictions, and indentities.

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​Objective 1: Decide whether a number is a solution of a linear equations.

​If the variable in an equation can be replaced with a real number that makes the statment true, the that number is a solution of the equation.

​7 is a solution for the equation 

​An equation is solved by finding its solution set. The solution set for this equation is {7}.

​If multiple equations have the same solution set, then they are Equivalent Equations. The solution set is {2}

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​Objective 2: Solve linear adding and mutiplying

​Solve 5x - 3x - 6 = 14 + 8x + 4.

​The goal is to isolate the variable on one side of the equation.

​Combine Like Terms

Add 6 to both sides

Subtract 8x from both sides

​Divide both sides by -6

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​Solving a Linear Equation in One Variable

  • ​Step 1: Clear Fractions - Eliminate any fractions by muliplying each side by the least common denominator.

  • ​Step 2: Simplify each side separately - Use distributive property to clear parantheses and combine like terms as needed.

  • ​Step 3: Isolate the variable terms on one side. Use the addition property to get all terms with variables on one side of the equation and all numbers on the other.

  • ​Step 4: Isolate the varaible - Use the multiplication property to get an equation with just the variable (coefficient of 1) on one side.

  • ​Step 5: Check - Substitute the proposed solution into the original equation.

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​Objective 3: Using the Distibutive Property

​Solve 2(k - 5) + 3k = k + 6

  • ​Since there are no fractions, Step 1 does not apply.

Distributive Property

Multiply

Combine Like Terms

Add 10 to both sides

Subtract k from both sides

Divide both sides by 4

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​Obj. 4: Solving Linear Equations w/ Fractions

​Solve

​Start by eliminating the fractions. Multiply both sides by the LCD, 6.

​The LCD is 6.

​ Distributive Property

​ Multiply;

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​Obj. 4: Solving Linear Equations w/ Fractions

​Distributive Property

​Multiply

​Combine Like Terms

​Add 17 to both sides

​Combine Like Terms

​Divide both sides by 7

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Advance Algebra with Trigonometry

​Section 2-1: Linear Equations in One Variable

by Jeremy Adelmann

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