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Proportions in Triangles

Proportions in Triangles

Assessment

Presentation

Mathematics

9th - 12th Grade

Medium

CCSS
HSG.CO.C.9, HSG.SRT.B.4, HSG.SRT.B.5

+3

Standards-aligned

Created by

Deb Scott

Used 18+ times

FREE Resource

4 Slides • 22 Questions

1

Proportions in Triangles

by Deb Scott

Objective: Use the Side-Splitter Theorem and the

​Triangle-Angle- Bisector Theorem

2

media

3

Multiple Choice

Question image
Find the missing length.
1
21
2
18
3
16
4
24

4

Multiple Choice

Question image
Find the missing length.
1
6
2
8
3
5
4
None of these

5

Multiple Choice

Question image

Solve for x.

1

10

2

5

3

7

4

4

6

Multiple Choice

Question image

The Side Splitter Theorem states that If a line is parallel to one side of a triangle and intersects the other two sides, then ABBC =AE?\frac{AB}{BC\ }=\frac{AE}{?} What is the question mark?

1

BE

2

CD

3

AD

4

ED

7

media

8

Fill in the Blank

Type answer...

9

Fill in the Blank

Type answer...

10

Multiple Choice

Question image
Solve for x.
1
8
2
6
3
5
4
-8

11

Multiple Choice

Question image

Which proportion should you use to find x?

1

15 / x = 7 / 14

2

x / 7 = 14 / 15

3

7 / x = 15 / 14

4

x / 15 = 7 / 14

12

media

13

Multiple Choice

Question image
Find the value of x.
1
17.5
2
10
3
7
4
17

14

Multiple Choice

Question image

Find the missing length.

1

10

2

21

3

35

4

9

15

Multiple Choice

Question image

Find the missing length.

1

25

2

15

3

6

4

16

16

Multiple Choice

Question image

Find the missing length.

1

15

2

11

3

35

4

8

17

Multiple Choice

Question image

Solve for x.

1

5

2

10

3

3

4

8

18

Multiple Choice

Question image

Solve for x.

1

10

2

9

3

6

4

5

19

Multiple Choice

Question image

Find the missing length indicated.

1

45

2

28

3

7

4

30

20

Multiple Choice

Question image

Find the missing length indicated.

1

3

2

12

3

27

4

24

21

Multiple Choice

Question image

Find the missing length indicated.

1

5

2

54

3

3

4

35

22

Multiple Choice

Question image

Solve for x.

1

8

2

4

3

7

4

5

23

Multiple Choice

Question image

Solve for x.

1

8

2

7

3

5

4

10

24

Multiple Choice

Question image

Solve for x.

1

4

2

9

3

3

4

7

25

Multiple Choice

Question image

Solve for x.

1

9

2

8

3

5

4

7

26

Poll

Which is easier

Side Splitter Theorem

Angle Bisector Theorem

Neither one is easier than the other

Both are just as easy

Proportions in Triangles

by Deb Scott

Objective: Use the Side-Splitter Theorem and the

​Triangle-Angle- Bisector Theorem

Show answer

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