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Module 5 Test Review

Module 5 Test Review

Assessment

Presentation

Mathematics

8th - 12th Grade

Medium

Created by

Bette Horsington

Used 5+ times

FREE Resource

5 Slides • 20 Questions

1

Module 5 Test Review

By Bette Horsington (VVA Algebra 2)

2

Multiple Choice

A parabola that has a minimum value has a U shape.

1

True

2

False

3

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4

Multiple Choice

Which square root equation shows a vertical compression, a right horizontal translation, and a downward vertical translation?

1

y=x2+3y=\sqrt[]{x-2}+3  

2

y=2x5+2y=2\sqrt[]{x-5}+2  

3

y=45x52y=\frac{4}{5}\sqrt[]{x-5}-2  

4

y=3x54y=3\sqrt[]{x-5}-4  

5

Multiple Choice

Which square root equation shows a vertical stretch, an y-axis reflection, a left horizontal translation, and a upward vertical translation?

1

y=2x1+3y=2\sqrt[]{-x-1}+3  

2

y=12x2+3y=\frac{1}{2}\sqrt[]{-x-2}+3  

3

y=2x+5+4y=-2\sqrt[]{x+5}+4  

4

y=23x2+3y=\frac{2}{3}\sqrt[]{-x-2}+3  

6

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7

Multiple Choice

Which cube root equation shows a vertical compression, a left horizontal translation, and a downward vertical translation?

1

y=x+233y=\sqrt[3]{x+2}-3  

2

y=13x234y=\frac{1}{3}\sqrt[3]{x-2}-4  

3

y=3x+236y=3\sqrt[3]{x+2}-6  

4

y=23x+234y=\frac{2}{3}\sqrt[3]{x+2}-4  

8

Multiple Choice

Which cube root equation shows a vertical stretch, an x-axis reflection, a right horizontal translation, and a upward vertical translation?

1

y=2x23+3y=2\sqrt[3]{x-2}+3  

2

y=2x13+3y=-2\sqrt[3]{x-1}+3  

3

y=12x13+3y=-\frac{1}{2}\sqrt[3]{x-1}+3  

4

y=2x+13+4y=-2\sqrt[3]{x+1}+4

9

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  • need start value (which is max/min)

  • either increasing or decreasing

  • as x approaches start x , then y approaches start y

  • Domain and Range is greater than = corresponding start value (if increasing)​

square root graph

  • need center value (use this x value in increase or decrease interval)

  • graph either decreasing or increasing

  • Domain and Range all reals

  • if increasing then as x goes to + infinity then y goes to+ infinity and as x goes to - infinity then y goes to - infinity

​cube root graph

10

Fill in the Blanks

Type answer...

11

Fill in the Blanks

Type answer...

12

Multiple Choice

What is the y intercept for y=3(x2)25y=3\left(x-2\right)^2-5  

1

(2,0)\left(2,0\right)  

2

(0,5)\left(0,5\right)  

3

(0,7)\left(0,7\right)  

4

(7,0)\left(7,0\right)  

13

Multiple Choice

What is increase and decrease interval for y=3(x2)25y=3\left(x-2\right)^2-5  

1

increase: <x<increase:\ -\infty<x<\infty   decrease: <x<decrease:\ -\infty<x<\infty  

2

increase: 2<x<increase:\ 2<x<\infty   decrease: <x<2decrease:\ -\infty<x<2  

3

increase: <x<2increase:\ -\infty<x<2   decrease: 2<x<decrease:\ 2<x<\infty  

4

increase: noneincrease:\ none   decrease: <x<decrease:\ -\infty<x<\infty  

14

Fill in the Blanks

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15

Fill in the Blanks

Type answer...

16

Fill in the Blanks

Type answer...

17

Multiple Choice

In y=x2+3y=\sqrt[]{x-2}+3  as xx\rightarrow\infty  

1

yy\rightarrow-\infty  

2

ϕ\phi  

3

yy\rightarrow\infty  

4

y3y\rightarrow3  

18

Multiple Choice

In y=x2+3y=\sqrt[]{x-2}+3  as x2x\rightarrow2  

1

yy\rightarrow-\infty  

2

ϕ\phi  

3

yy\rightarrow\infty  

4

y3y\rightarrow3  

19

Fill in the Blanks

Type answer...

20

Fill in the Blanks

Type answer...

21

Multiple Choice

Describe the of increase interval of y=x23+3y=\sqrt[3]{x-2}+3  

1

<x<-\infty<x<\infty  

2

<x<2,   2<x<-\infty<x<2,\ \ \ 2<x<\infty  

3

ϕ\phi  

4

<x<2-\infty<x<2  

22

Multiple Choice

Describe the end behavior of y=x23+3y=\sqrt[3]{x-2}+3  

1

x  then  yx\ \rightarrow-\infty\ then\ \ y\rightarrow-\infty   x  then yx\rightarrow\infty\ \ then\ y\rightarrow\infty  

2

x  then  yx\ \rightarrow-\infty\ then\ \ y\rightarrow\infty    x  then  yx\ \rightarrow\infty\ then\ \ y\rightarrow-\infty  

3

ϕ\phi  

4

  x  then  yx\ \rightarrow-\infty\ then\ \ y\rightarrow-\infty   x  then  yx\ \rightarrow\infty\ then\ \ y\rightarrow-\infty  

23

Fill in the Blanks

Type answer...

24

Multiple Choice

x-intercepts and zeros are at the same location. True or False

1

True

2

False

25

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Module 5 Test due tonight at 11:59pm ​

Module 5 Test Review

By Bette Horsington (VVA Algebra 2)

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