

Solving Log Equations Guided Practice
Presentation
•
Mathematics
•
12th Grade
•
Medium
Stephanie Balbaneda
Used 5+ times
FREE Resource
10 Slides • 11 Questions
1
By Stephanie Balbaneda
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How to convert between log and exponential forms
The 3 Log properties: Product, Quotient and Power
How to use the properties to expand/condense log expressions
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Product Rule: loga(m*n) = logam+logan
Quotient Rule: loga(m/n) = logam-logan
Exponent Rule: y*loga(m) = loga(my)
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Follow the order of operations
When condensing, always do the Power Property first
6
Multiple Choice
Condense into one log: 2log3(x)+log3(y) Remember to use the power property first!
log3(2xy)
log3(x2y)
log3(xy)2
2log3(xy)
7
Multiple Choice
Condense into a single log expression.
8
Multiple Choice
Expand: this has a mix of Product and Quotient Prop.: log(yz8x)
log8+logx-logy-logz
log8+logx-logy+logz
log(8x)-log(yz)
8logx-ylogz
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Multiple Choice
Expand: log(nm3)
logm-log3-logn
3logm+logn
3logm-logn
3log(m-n)
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If loga(x) = loga(y), the x = y
So log(x) = log(7), this means that x = 7
Recall we had a very similar rule when solving exponentials, bx = by, x = y, why does it make sense that we have a similar rule?
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12
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Multiple Choice
Solve log2(x+8)=log264
x=16
x=24
x=56
x=40
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Multiple Choice
Solve log8(3x+7)=log8(7x+4)
x=43
x=3
x=6
x=34
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16
Multiple Choice
Solve log6x+log69=log654
x=6
x=45
x=7
x=36
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18
Multiple Choice
Solve
log7n=32log78
n=1
n=3
n=6
n=4
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20
Multiple Choice
Solve log9(3u+14)−log95=log92u
u=4
u=6
u=2
u=1
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By Stephanie Balbaneda
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