
Volumetric Analysis
Presentation
•
Chemistry
•
11th - 12th Grade
•
Medium
Standards-aligned
Angela Toh
Used 5+ times
FREE Resource
8 Slides • 15 Questions
1
Volumetric Analysis
By Angela Toh
2
3
Multiple Choice
The point in an acid-alkali titration at which the reactants just react completely with each other is called the __________ point.
equivalence point
end point
4
Multiple Choice
A chemical used to show the end point of titration is called
base
indicator
pipette
acid
5
Multiple Choice
The quantity of liquid delivered by the burette in a titration is called
burette reading
aliquot
concentration
titre
6
7
Multiple Choice
To prepare a solution of accurately known volume, use a
measuring cylinder
beaker
concial flask
volumetric flask
8
Multiple Choice
A standard solution is a solution with accurately known concentration.
True
False
9
10
11
12
Multiple Choice
What volume of water is required to dilute 120 cm3 of 10 mol dm–3 sulfuric acid to a concentration of 2 mol dm–3?
360 cm3
480 cm3
600 cm3
720 cm3
13
Multiple Choice
3.75 dm3 of distilled water are added to 250.0 cm3 of 3.20 mol dm–3 sodium hydroxide solution. What is the molarity of the diluted solution?
0.200 mol dm-3
0.213 mol dm-3
2.00 mol dm-3
2.13 mol dm-3
14
Multiple Choice
What volume of 5.0 mol dm–3 hydrochloric acid is required to prepare 250 cm3 of a 0.40 mol dm–3 solution?
10 cm3
20 cm3
30 cm3
40 cm3
15
Fill in the Blanks
Beaker A contains 500 cm3 of 1.0 M of HCl. A student pipettes 25 cm3 of HCl
from beaker A and places it in Beaker B. The student then adds water to Beaker B such that the total volume of solution in Beaker B is 250 cm3. What is the final concentration (in terms of M) of HCl in Beaker B?
Type answer...
16
17
18
Multiple Choice
A 4 g sample of sodium hydroxide, NaOH, is dissolved in water and made up to 500
cm3 of aqueous solution. What is the concentration of the resulting solution?
0.1 mol dm-3
0.2 mol dm-3
0.5 mol dm-3
1 mol dm-3
19
Open Ended
27.82 g of hydrated sodium carbonate crystals, Na2CO3. xH2O, was dissolved in water and made up to 1.000 dm3. 25.00 cm3 of this solution was neutralized by 48.80 cm3 of hydrochloric acid of concentration 0.1000 mol dm-3.
(a) Write an equation for the reaction between sodium carbonate and hydrochloric
acid, including the state symbols.
20
Fill in the Blanks
27.82 g of hydrated sodium carbonate crystals, Na2CO3. xH2O, was dissolved in water and made up to 1.000 dm3. 25.00 cm3 of this solution was neutralized by 48.80 cm3 of hydrochloric acid of concentration 0.1000 mol dm-3.
(b) Calculate the molar concentration of the sodium carbonate solution neutralized
by the hydrochloric acid.
Type answer...
21
Fill in the Blanks
27.82 g of hydrated sodium carbonate crystals, Na2CO3. xH2O, was dissolved in water and made up to 1.000 dm3. 25.00 cm3 of this solution was neutralized by 48.80 cm3 of hydrochloric acid of concentration 0.1000 mol dm-3.
(c) Determine the mass of sodium carbonate neutralized by the hydrochloric acid
and hence the mass of sodium carbonate present in the 1.000 dm3 of solution.
Type answer...
22
Fill in the Blanks
27.82 g of hydrated sodium carbonate crystals, Na2CO3. xH2O, was dissolved in water and made up to 1.000 dm3. 25.00 cm3 of this solution was neutralized by 48.80 cm3 of hydrochloric acid of concentration 0.1000 mol dm-3.
(d) Calculate the mass of water in the hydrated crystals.
Type answer...
23
Fill in the Blanks
27.82 g of hydrated sodium carbonate crystals, Na2CO3. xH2O, was dissolved in water and made up to 1.000 dm3. 25.00 cm3 of this solution was neutralized by 48.80 cm3 of hydrochloric acid of concentration 0.1000 mol dm-3.
(d) Use the mass of water in the hydrated crystals to find the value of
x.
Type answer...
Volumetric Analysis
By Angela Toh
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