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Limiting Reagents and Percentage Yield

Limiting Reagents and Percentage Yield

Assessment

Presentation

Chemistry, Science

10th - 12th Grade

Practice Problem

Medium

NGSS
HS-PS1-7

Standards-aligned

Created by

Abby Fancsali

Used 51+ times

FREE Resource

11 Slides • 10 Questions

1

Limiting Reagents and Percentage Yield

2

Introduction

  • In an ideal experiment, we have the exact amount of each reactant needed to produce a product, and we end up with the exact amount of product we are supposed to

  • This is not​ always the reality, we often deal with limiting reactants and wind up with less or more than we were supposed to

media

3

What is a Limiting Reactant?

  • A limiting reactant is the reactant the limits how much of a product can be produced from a reactant.

  • It is completely used up​ when the reaction takes place

  • the reactant not used up is known as the excess reactant​

4

Solving for Limiting Reactant Example 1

Silicon dioxide reacts with hydrogen Fluoride in the following reaction​:

SiO2​+4HF → SiF4 + 2H2O

If 6.0 mol HF is added to 4.5 mol SiO2, Which is the limiting reactant?​

  • Step 1: Identify one of the products in the reaction to measure your production by. Let's use SiF4, since it exists as one mole in the equation

  • Step 2: Convert our given moles of reactants to moles of our products

5

Fill in the Blank

Using the equation

SiO2​+4HF → SiF4 + 2H2O

How many moles of SiF4 can we produce with 6.0 mol of HF?

(Round to 1 Decimal Place)

6

Fill in the Blank

Using the equation

SiO2​+4HF → SiF4 + 2H2O

How many moles SiF4 can we produce with 4.5 mol HF?

(Round to 1 Decimal Place)

7

Solving for Limiting Reactant Example 1

Silicon dioxide reacts with hydrogen Fluoride in the following reaction​:

SiO2​+4HF → SiF4 + 2H2O

If 6.0 mol HF is added to 4.5 mol SiO2, Which is the limiting reactant?​

  • Step 3: Identify which reactant makes less with the given amounts

  • 6 mol HF can make 1.5 mol SiF4

  • 4.5 mol SiO2 can make 4.5 mol of SiF4

  • Since HF can only make 1.5 mol, it is the limiting reagent

8

Solving for Limiting Reactant Example 2

Iron oxide is made in the lab by combining iron with steam in the following reaction

3 Fe + 4 H2O→​Fe3O4 + 4 H2

When 36 grams of H2O is mixed with 67.0 grams of Fe, which is the limiting reagent?​

  • Step 1: Pick a product to measure your yield by. Which Product is the easiest to work with?

9

Multiple Choice

In the equation

3 Fe + 4 H2O→​Fe3O4 + 4 H2,

Which product will give the simples ratio to calculate with?

1

Fe3O4

2

H2

10

Solving for Limiting Reactant Example 2

Iron oxide is made in the lab by combining iron with steam in the following reaction

3 Fe + 4 H2O→​Fe3O4 + 4 H2

When 36 grams of H2O is mixed with 67.0 grams of Fe, which is the limiting reagent?​

  • Step 1: Pick a product to measure your yield by. We will use Fe3O4

  • Step 2: Convert both reactants from grams to moles, then to moles of Fe3O4

11

Fill in the Blank

Using the equation 3 Fe + 4 H2O→​Fe3O4 + 4 H2

how many moles of Fe3O4 are produced from 36.0 g of H2O?

(Round to three decimal places)

12

Fill in the Blank

Using the equation 3 Fe + 4 H2O→​Fe3O4 + 4 H2

how many moles of Fe3O4 are produced from 67.0 g of Fe?

(Round to three decimal places)

13

Multiple Choice

Iron oxide is made in the lab by combining iron with steam in the following reaction

3 Fe + 4 H2O→​Fe3O4 + 4 H2

When 36 grams of H2O is mixed with 67.0 grams of Fe, which is the limiting reagent?​

1

Fe

2

H2O

14

Percentage Yield

  • In equations we calculate the theoretical yield, or the maximum amount of a product that can be produced from a given amount

  • In reality, it is hard to get the maximum amount for a variety of reasons

  • The actual yield is the measured amount of a product in a reaction​

  • To determine how efficient a reaction is, chemists use the following equation calculate the percentage yield​

15

Percentage Yield Practice Problem 1

​Chlorobenzene is a used in the production of a variety of chemicals. In order to be used, it is prepared with chlorine in the following equation:

​When 36.8 g C6H6 react with an excess of Cl2 the actual yield of C6H5Cl is 38.8 g. What is the Percentage Yield?

  • Step 1: Set up your Stoichiometry Equation

  • Step 2: Find the masses of C6H6 and C6H5Cl

  • Step 3: Plug in your masses and solve​

16

Percentage Yield Practice Problem 1

​Chlorobenzene is a used in the production of a variety of chemicals. In order to be used, it is prepared with chlorine in the following equation:

​When 36.8 g C6H6 react with an excess of Cl2 the actual yield of C6H5Cl is 38.8 g. What is the Percentage Yield?

  • Step 1: Set up your Stoichiometry Equation

  • Step 2: Find the masses of C6H6 and C6H5Cl

  • Step 3: Plug in your masses and solve​ for Theoretical yield

17

Fill in the Blank

What is the mass of C6H6? Round to two Decimal places

18

Fill in the Blank

What is the mass of C6H5Cl? Round to two Decimal places

19

Fill in the Blank

What is the Theoretical yield of C6H5Cl you get from 36.8 g of C6H6? Round to a whole number

20

Percentage Yield Practice Problem 1

​Chlorobenzene is a used in the production of a variety of chemicals. In order to be used, it is prepared with chlorine in the following equation:

​When 36.8 g C6H6 react with an excess of Cl2 the actual yield of C6H5Cl is 38.8 g. What is the Percentage Yield?

  • Step 1: Set up your Stoichiometry Equation

  • Step 2: Find the masses of C6H6 and C6H5Cl

  • Step 3: Plug in your masses and solve​ for Theoretical yield

  • Step 4: solve for Percentage Yield​

21

Fill in the Blank

If you end up with 38.8 g of C5H5Cl, What is the percentage yield of C6H5Cl you got from 36.8 g of C6H6? Round to one decimal place

Limiting Reagents and Percentage Yield

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