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Solutions

Solutions

Assessment

Presentation

Chemistry, Science

10th - 12th Grade

Practice Problem

Hard

Created by

Abby Fancsali

Used 29+ times

FREE Resource

13 Slides • 7 Questions

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Solutions

By Abby Fancsali

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Recall

  • Mixtures are a combination of substances

    • Can heterogenous or homogenous

      • Heterogenous Mixtures: large particles that ​can be easily seen and separated

        • Suspensions: a heterogenous mixture that separates on its own over time

          • Clay in water

        • Colloids: a heterogenous mixture that does not separate on its own over time

          • Milk

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Homogenous solutions are Solutions

  • Solution: any mixture that is homogenous on a microscopic level

    • Usually a liquid, but can be solid or gas as well

      • Solid solutions tend to be alloys like brass

    • ​Liquids Solutions have two parts

      • Solvent: The main ingredient that you dissolve substances in

        • Water is called the universal solvent because it dissolves so many things into aqueous solutions

      • Solute: the ingredient you are dissolving

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Separating Mixtures-Physical Means

  • There are many ways to separate mixtures into their components, and what you do depends on your ultimate goal

    • Physical methods

      • Decanting

      • Centrifuging

      • Filtration

      • Evaporation​

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Separating Mixtures- other methods

  • Chromatography: separates components of a mixture based on how quickly different molecules dissolved in a mobile phase solvent move along a solid plane

  • Distillation Separates mixtures based on evaporation point

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Concentration

  • In a solution, the solute is distributed evenly throughout the solvent

  • Concentration: the ratio of solute to solvent in a solution

    • When a solution has a low concentration it is Diluted

      • Different ways to measure concentration

        • Parts per million

        • Molarity

        • Molality

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Calculating Concentration: Parts per million (ppm)

  • Parts per million is a measure of concentration used in measuring pollution

    • Involves very low levels of concentration

    • Measures how many grams of solute are in 1 million grams of solution

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Calculating Concentration: Parts per million (ppm)

  • Sample Problem: A chemical analysis shows that there are 2.2 mg of lead in 500g of a water sample. Convert this measurements to parts per million

    • Step 1: Identify your givens

      • 2.2 mg Pb

      • 500 g H2O

    • Step 2: Identify what you need to do

      • Need lead in grams

      • convert your ratio to ppm​

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Calculating Concentration: Parts per million (ppm)

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Calculating Concentration: Molarity (M)

  • It is often more useful to describe concentrations in terms of the number of solute particles in a solution rather than the mass of the solute particles

  • Molarity: Measures the number of moles of solute that are in one liter of a solution

    • read as "moles per Liter"​

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Calculating Concentration: Molarity (M)

  • Sample Problem: What is the Molarity of a potassium chloride solution that has a volume of 400.0 mL and contains 85 g KCl

    • Step one Identify what you have

      • Volume of substance = 400 mL

      • Mass of Solute= 85 g KCl

    • Step 2: Identify what you need to solve

      • Moles of solute

      • Volume in Liters​

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Calculating Concentration: Molarity (M)

  • Sample Problem: What is the Molarity of a potassium chloride solution that has a volume of 400.0 mL and contains 85 g KCl

    • Step three: plug in your values to the Molarity Equation

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Using Molarity in Solution Stoichiometry

  • Sample Problem: What volume in mL of a 0.5 M solution of CuSO4 is needed to react with an excess of aluminum to provide 11.0 g of Copper?

  • Molar Mass of Cu = 63.55 g/mol

  • 0.5 M solution has 0.5 moles in 1 liter​

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Solutions

By Abby Fancsali

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