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Pyramid - Identifying Areas

Pyramid - Identifying Areas

Assessment

Presentation

Mathematics

9th Grade

Easy

Created by

Lester Orellana

Used 7+ times

FREE Resource

5 Slides • 11 Questions

1

Pyramid -

Identifying faces

2

Multiple Choice

Question image

What is the base of the Front Face?

1

10 cm

2

8 cm

3

6 cm

4

Slant height

3

Multiple Choice

Question image

What is the Height of the Front Face?

1

10 cm

2

8 cm

3

6 cm

4

Slant height

4

Multiple Choice

Question image

What is the Height of the Pyramid?

1

10 cm

2

8 cm

3

6 cm

4

Slant height

5

Multiple Choice

Question image

What is the correct option for the Area of the front face?

(Base × Heigh)2\frac{\left(Base\ \times\ Heigh\right)}{2}  

1

(10×8)2\frac{\left(10\times8\right)}{2}  

2

(10×6)2\frac{\left(10\times6\right)}{2}  

3

(10×slant height)2\frac{\left(10\times slant\ height\right)}{2}  

6

Multiple Choice

Question image

What is the Height of the back (rear) Face?

1

10 cm

2

8 cm

3

6 cm

4

Slant height

7

Multiple Choice

Question image

What is the correct option for the Area of the left (or side) face?

(Base × Height)2\frac{\left(Base\ \times\ Height\right)}{2}  

1

(8×8)2\frac{\left(8\times8\right)}{2}  

2

(8×6)2\frac{\left(8\times6\right)}{2}  

3

(8×slant height)2\frac{\left(8\times slant\ height\right)}{2}  

8

Multiple Choice

Question image

Choose the correct option to find the slant height of the front face:

c2=a2+b2c^2=a^2+b^2  

1

s=42+62s=\sqrt[]{4^2+6^2}   

2

s=82+62s=\sqrt[]{8^2+6^2}   

3

s=102+62s=\sqrt[]{10^2+6^2}   

4

s=52+62s=\sqrt[]{5^2+6^2}  

9

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10

Multiple Choice

Question image

Choose the correct option to find the slant height of the left face:

c2=a2+b2c^2=a^2+b^2  

1

s=42+62s=\sqrt[]{4^2+6^2}   

2

s=82+62s=\sqrt[]{8^2+6^2}   

3

s=102+62s=\sqrt[]{10^2+6^2}   

4

s=52+62s=\sqrt[]{5^2+6^2}  

11

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12

Multiple Choice

Question image

Choose the correct option to find the area of Pyramid's base:

1

A=10×8A=10\times8   

2

A=102+82A=\sqrt[]{10^2+8^2}   

3

A=(10×8)2A=\frac{\left(10\times8\right)}{2}  

13

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14

Multiple Choice

Question image

What is the correct option for the Area of the front face?

(Base × Height)2\frac{\left(Base\ \times\ Height\right)}{2}  

1

(10×8)2\frac{\left(10\times8\right)}{2}  

2

(10×6)2\frac{\left(10\times6\right)}{2}  

3

(10×slant height)2\frac{\left(10\times slant\ height\right)}{2}  

15

Multiple Choice

Question image

Choose the correct option to find the slant height of the front face:

c2=a2+b2c^2=a^2+b^2  

1

s=42+62s=\sqrt[]{4^2+6^2}   

2

s=82+62s=\sqrt[]{8^2+6^2}   

3

s=102+62s=\sqrt[]{10^2+6^2}   

4

s=52+62s=\sqrt[]{5^2+6^2}  

16

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Pyramid -

Identifying faces

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