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3.3 Equation of a Circle Day 1

3.3 Equation of a Circle Day 1

Assessment

Presentation

Mathematics

10th Grade

Practice Problem

Medium

Created by

Lilibeth Villaran

Used 6+ times

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23 Slides • 12 Questions

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3.3 Equation of a Circle

By Lilibeth Villaran

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Learning Targets

I can ​

Lesson 3: Equation of a Circle

  • Illustrate the center-radius form of the equation of a circle

  • Determine the center and radius of a circle given its equation and vice versa

  • solve problem involving circle​

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Open Ended

What makes a circle unique?

Think about the shape and properties of a circle.

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A set of points that is equidistant from a fixed point called the center.

Definition

Circle

Lesson 3: Equation of a Circle

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Standard Form of a Circle

Lesson 3: Equation of a Circle

​Center -Radius Form

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Example 1. What is the standard form of the equation of a circle?

Lesson 3: Equation of a Circle

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Identify the center and radius of the given circle.

​​

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Example 1. What is the standard form of the equation of a circle?

Lesson 3: Equation of a Circle

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Example 2. What is the standard form of the equation of a circle?

Lesson 3: Equation of a Circle

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Let's play!

Lesson 3: Equation of a Circle

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Multiple Choice

What is the standard form of the equation of the circle whose center is at (5, 6) and the radius is 4?

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(x+5)2+(x+6)2=16\left(x+5\right)^2+\left(x+6\right)^2=16  

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(x5)2+(y6)2=16\left(x-5\right)^2+\left(y-6\right)^2=16  

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(x5)2+(y6)2=4\left(x-5\right)^2+\left(y-6\right)^2=4  

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(x+5)2+(x+6)2=4\left(x+5\right)^2+\left(x+6\right)^2=4  

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Multiple Choice

What is the standard equation of a circle whose center is at (-3,4) and the radius is 7?

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(x+3)2+(y4)2=49\left(x+3\right)^2+\left(y-4\right)^2=49  

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(x3)2+(y+4)2=49\left(x-3\right)^2+\left(y+4\right)^2=49  

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(x3)2+(y+4)2=7\left(x-3\right)^2+\left(y+4\right)^2=7  

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(x+3)2+(y4)2 =7\left(x+3\right)^2+\left(y-4\right)^{2\ }=7  

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Multiple Choice

What is the center-radius form of a circle with a radius of 12 and center at (-3, -5)?

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(x3)2+(x5)2=12\left(x-3\right)^2+\left(x-5\right)^2=12  

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(x3)2+(y5)2=144\left(x-3\right)^2+\left(y-5\right)^2=144  

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(x+3)2 +(x+5)2=144\left(x+3\right)^{2\ }+\left(x+5\right)^2=144  

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(x+3)2+(y+5)2=12\left(x+3\right)^2+\left(y+5\right)^2=12  

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Multiple Choice

Write the standard form of the equation of the circle with radius of 6\sqrt[]{6}  and center at (8, 0).

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(x8)2+y2=6\left(x-8\right)^2+y^2=6  

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(x8)2+y2=36\left(x-8\right)^2+y^2=36  

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(x8)2+y=6\left(x-8\right)^2+y=6  

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(x8)2+y2=6\left(x-8\right)^2+y^2=\sqrt[]{6}  

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Multiple Choice

What is the center-radius form of a circle with a diameter of 20 units and a center at (-1, 1)?

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(x+1)2+(y1)2=400\left(x+1\right)^2+\left(y-1\right)^2=400  

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(x1)2+(y+1)2=400\left(x-1\right)^2+\left(y+1\right)^2=400  

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(x1)2+(y+1)2=100\left(x-1\right)^2+\left(y+1\right)^2=100  

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(x+1)2+(y1)2=100\left(x+1\right)^2+\left(y-1\right)^2=100  

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You did great!

Lesson 3: Equation of a Circle

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Finding the center and radius of a circle given the equation

Lesson 3: Equation of a Circle

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center (h,k)

radius

Lesson 3: Equation of a Circle

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center (h,k)

radius

Lesson 3: Equation of a Circle

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center (h,k)

radius

Lesson 3: Equation of a Circle

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Let's have a drill!

Lesson 3: Equation of a Circle

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Multiple Choice

What is the center and radius of a circle with equation of (x6)2+(y+1)2=81\left(x-6\right)^2+\left(y+1\right)^2=81  ?

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C(-6, 1) and r= 81

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C(-6,1) and r=9

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C (6,-1) and r=9

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C(6, -1) and r=81

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Multiple Choice

What is the radius and center of a circle with an equation of x2 + y2=5x^2\ +\ y^2=5  

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C(1,1) and r=5

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C(0,0) and r= 5\sqrt[]{5}  

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C(0,0) and r= 5

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C(0,0) and r = 25

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Multiple Choice

Find the radius and center of a circle with equation of x2+(y+4)2=10x^2+\left(y+4\right)^2=10  

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C(0, 4) and r= 10\sqrt[]{10}  

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C(0,-4) and r=100

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C(1, 4) and r= 10

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C (0, -4) and r= 10\sqrt[]{10}  

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You did well!

The next questions will be tricky.​ Let's go!

Lesson 3: Equation of a Circle

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Multiple Choice

Question image

Write the equation of the circle in standard form.

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(x1)2+(y1)2=5\left(x-1\right)^2+\left(y-1\right)^2=5  

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(x1)2+(y1)2=16\left(x-1\right)^2+\left(y-1\right)^2=16  

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(x1)2+(y1)2=25\left(x-1\right)^2+\left(y-1\right)^2=25  

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(x+1)2+(y+1)2=4\left(x+1\right)^2+\left(y+1\right)^2=4  

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Multiple Choice

Question image

Find the center-radius form of the equation of the circle.

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(x+2)2+(y1)2=8\left(x+2\right)^2+\left(y-1\right)^2=8  

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(x2)2+(y1)2=64\left(x-2\right)^2+\left(y-1\right)^2=64  

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(x2)2+(y+1)2=64\left(x-2\right)^2+\left(y+1\right)^2=64  

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(x+2)2+(y1)2=64\left(x+2\right)^2+\left(y-1\right)^2=64  

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Multiple Choice

Question image

What is the equation of the circle in standard form?

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x2+y2=15x^2+y^2=15  

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x2+y2=125x^2+y^2=125  

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x2+y2=225x^2+y^2=225  

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x2+y2=0x^2+y^2=0  

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Great work!

Lesson 3: Equation of a Circle

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Solving problems involving circle

Some text here about the topic of discussion.

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Some text here about the topic of discussion.

Write an equation of a circle whose center is at (4, 3) and passing through (1, 6).

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Some text here about the topic of discussion.

Write an equation of a circle whose center is at (4, 3) and passing through (1, 6).

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Write an equation of a circle whose center is at (-5, 3) and passing through (-2, -1).

Some text here about the topic of discussion

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Write an equation of a circle whose center is at (-5, 3) and passing through (-2, -1).

Some text here about the topic of discussion

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ALA Activities

Please answer and submit in the class notebook.

Lesson 3: Equation of a Circle

  • Module 3 Activity 7

  • Module 3 Activity 8

  • Module 3 Activity 9

    Due on April 8, 2022

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Thank you!

Lesson 3: Equation of a Circle

3.3 Equation of a Circle

By Lilibeth Villaran

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