
Luas dan Volume Limas
Presentation
•
Mathematics
•
8th Grade
•
Practice Problem
•
Hard
Ilham Ilham
Used 8+ times
FREE Resource
11 Slides • 0 Questions
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2
a. Limas Segitiga
Mempunyai 4 titik sudut (A,B,C, dan D)
Mempunyai 4 bidang sisi, yaitu ABC, ABD, BCD, dan ACD.
Mempunyai 6 rusuk.
OT disebut garis tinggi.
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Sifat-Sifat Limas
3
Mempunyai 5 titik sudut.
Mempunyai 5 bidang sisi.
Mempunyai 8 titik rusuk
Mempunyai 2 bidang diagonal sisi.
Mempunyai garis tinggi t
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b. Limas Segiempat
4
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Luas Permukaan Limas
5
Luas Permukaan Limas
Luas Permukaan Limas =
= Luas alas + Jumlah luas bidang tegak
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Contoh :
Alas limas T.ABCD pada gambar di samping berbentuk persegi dengan panjang sisi 12 cm. TP adalah garis tinggi pada segitiga ABC. Jika tinggi limas tersebut 8 cm, hitunglah :
a. panjang TP
b. luas permukaan limas
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a. OP = 1/2 AB = 6 cm.
ΔTOP siku-siku di O, maka :
TP2 = TO2 + OP2 (teorema Pythagoras)
TP2 = 82 + 62
TP2 = 64 + 36
TP2 = 100
TP = 10
Jadi, panjang TP adalah 10 cm.
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b. Luas permukaan limas
= luas alas + 4 x luas ΔBCT
= (s x s) + [ 4 x ( 1/2 x BC x TP) ]
= (12 x 12) + [ 4 x (1/2 x 12 x 10) ]
= 144 + 240
= 384
Jadi, luas permukaan limas tersebut adalah 384 cm2
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Volume Limas
Volume Limas = 1/3 x luas alas x tinggi
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Contoh soal:
Alas sebuah limas berbentuk segitiga siku-siku dengan panjang sisi 10 cm, 26 cm, dan 24 cm. Hitunglah tinggi limas tersebut jika volumenya 1.080 cm3 !
Subject | Subject
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11
Jawab :
V = 1/3 x Luas alas x tinggi
1.080 = 1/3 x ( 1/2 x alas segitiga x tinggi segitiga) x tinggi prisma
1.080 = 1/3 x (1/2 x 24 x 10 ) x t
1.080 = 1/3 x 120 x t
1.080 = 40t
t = 1.080/40
t = 27
jadi, tinggi limas tersebut adalah 27 cm.
Subject | Subject
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