Final Exam Review 2 - Similar Triangles and Quadratics

Final Exam Review 2 - Similar Triangles and Quadratics

By Tiffany Madison

Multiple Choice

Solve for g in the proportion

$$\frac{10}{h}=\frac{2}{10}$$  

• h=10

• h=2

• h=50

• h=100

Multiple Choice

Solve for n

$$\frac{n}{4}=\frac{8}{7}$$  

• 5

• 32

• 4

• 32/7

Similar Triangles -- same shape, different size

• Angles Must Be Congruent (the same size)

• Sides Must Be Proportion (the ratios of corresponding sides will be equivalent fractions

Multiple Choice

Are the triangles similar? (Hint: Find missing angles)

• Yes

• No

Multiple Choice

Which triangles are similar to triangle A?

• B

• C

• Both

• None

Multiple Choice

Are the triangles similar?

• Yes
• No

Multiple Choice

State if the triangles in each pair are similar. If so, state how you know they are similar.

• Yes, AA Similarity

• Yes, SSS Similarity

• Yes, SAS Similarity

• Not Similar

Multiple Choice

State if the triangles in each pair are similar. If so, state how you know they are similar. (Hint: Do not forgot about vertical angles)

• Yes, AA Similarity

• Yes, SSS Similarity

• Yes, SAS Similarity

• Not Similar

Multiple Choice

The triangles are similar by...

• SAS
• AA
• ASA
• SSS

Multiple Choice

If the triangles are similar, state how.

• SSS

• SAS

• AA

• Not similar.

Could be any kind SAS SSS or AA

Multiple Choice

How do these triangles appear to be similar?

• AA
• SAS
• SSS
• Not Similar

Multiple Choice

How do these triangles appear to be similar?

(Hint: Look for non-labeled parts!)

• AA

• SAS

• SSS

• Not Similar

Multiple Choice

How do these triangles appear to be similar?

• AA

• SAS

• SSS

• Not Similar

Multiple Choice

Find the missing length.

• 21
• 18
• 16
• 24

Multiple Choice

Solve for x.

• 10

• 5

• 7

• 4

Multiple Choice

Solve for x.

• 8
• 6
• 5
• -8

Multiple Choice

Which proportion should you use to find x?

• 15 / x = 7 / 14

• x / 7 = 14 / 15

• 7 / x = 15 / 14

• x / 15 = 7 / 14

Multiple Choice

Find the value of x.

• 17.5
• 10
• 7
• 17

As an example, if we have x² + 7x + 12

Integers that sum to 7 are:   0+7, 1+6, 2+5, 3+4

Factors of 12 are: 1⋅12, 2⋅6, 3⋅4

  

The only pair that are in common are 3 and 4.  

This means we can factor it to:   (x+3)(x+4)

  

Multiple Choice

Factor:

$$x^2+9x\ -36$$  

• (x + 12)(x  - 3)

• (x + 4)(x + 9)

• (x - 12)(x  - 3)

• (x - 12)(x  + 3)

Multiple Choice

Solve for the values of x:

(x - 5)(x - 1) = 0

• x = 5, 1

• x = 5, -1

• x = -5, 1

• x = -5, -1

Multiple Choice

Solve by factoring: x² + 3x - 18 = 0

• x = -3 and x = 6

• x = 3 and x = -6

• x = -9 and x = 2

• x = 9 and x = -2